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Deffense [45]
3 years ago
14

Please help, i im having trouble

Mathematics
2 answers:
Grace [21]3 years ago
5 0
The best way to solve this equation is Elimination.

If you want me to solve, comment immediately.

Thanks!! :)
adelina 88 [10]3 years ago
3 0

Answer:

Elimination

Step-by-step explanation:

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RoseWind [281]

Answer:

D is the answer

Step-by-step explanation:

7 0
3 years ago
Select the correct answer.
sineoko [7]

Answer:

A

Step-by-step explanation:

The plus 7 at the end will shift the graph 7 units up. Replace y with f(x).

Then we have g(x) = f(x) + 7. Adding 7 to y = f(x) will increase the y value by 7.

7 0
3 years ago
Read 2 more answers
Prove De Morgan's law by showing that each side is a subset of the other side by considering x ∈ A⎯⎯⎯ A ¯ ∩ B⎯⎯⎯ B ¯ .
adelina 88 [10]

Solution :

We have to prove that $\overline{A \cup B} = \overline{A} \cap \overline{B}$   (De-Morgan's law)

Let  $x \in \bar{A} \cap \bar{B}, $ then $x \in \bar{A}$ and $x \in \bar{B} $

and so $x \notin \bar{A}$ and $x \notin \bar{B} $.

Thus, $x \notin A \cup B$ and so $x \in \overline{A \cup B}$

Hence, $\bar{A} \cap \bar{B} \subset \overline{A \cup B}$   .........(1)

Now we will show that $\overline{A \cup B} \subset \overline{A} \cap \overline{B}$

Let $x \in \overline{A \cup B}$ ⇒ $x \notin A \cup B$

Thus x is present neither in the set A nor in the set B, so by definition of the union of the sets, by definition of the complement.

$x \in \overline{A}$ and  $x \in \overline{B}$

Therefore, $x \in \overline{A} \cap \overline{B}$ and we have $\overline{A \cup B} \subset \overline{A} \cap \overline{B}$  .............(2)

From (1) and (2),

$\overline{A \cup B} = \overline{A} \cap \overline{B}$

Hence proved.

3 0
2 years ago
A large chocolate bar has a base area of 47.1 square feet and it’s length is 0.7 feet longer than twice it’s width. Find the len
VLD [36.1K]

Answer:

The dimensions of the bar are width = 4.68099 feet and length = 10.06198 feet

Step-by-step explanation:

A chocolate bar has a rectangular shape, therefore it's area is given by the following formula:

area = width*length

In this case the length is 0.7 feet longer than twice the width, therefore:

length = 2*width + 0.7

Applying the second equation on the first one and using the data from the question we have:

47.1 = width*(2*width + 0.7)

47.1 = 2*width² + 0.7*width

2*width² + 0.7*width = 47.1

width² + 0.35*width = 23.55

width = \frac{-0.35 \pm \sqrt{0.35^2 -4*1*(-23.55)}}{2*1} = -0.175 \pm 4,85599

width = 4.68099 or width = -5.03099

Since the width can't be negative, it can only be 4.68099 feet.

length = 2*4.68099 + 0.7 = 10.06198 feet.

6 0
3 years ago
A bag contains only red and blue marbles. Yasmine takes one marble at random from the bag. The probability that she takes a red
mamaluj [8]

Let red marbles = X.

The probability is 1 out of 5, written as 1/5

1/5 in terms of red marbles is equal to the number of red marbles divided by 5x, where 5x is the total number of marbles.

1/5 = x/5x 

Now you have 5x total marbles, x red and 4x blue. 

Add 5 more red and the new probability is: 

(x+5)/(5x+5) = 1/3 

Simplify:

3x+15 = 5x+5 

Now solve for x:

Subtract 3x from both sides:

15 = 2x +5

Subtract 5 from each side:

2x = 10 

Divide both sides by 2:

x = 10/2

X = 5

There were originally 5 red marbles.

5 0
3 years ago
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