The formula you should use is Area = 1/2bh, in other words, area equals half times base times height. Now, substitute everything in, the equation should now be 221.16 = 1/2*b*29.1. This simplifies into 221.16 = 14.55b, now divide 14.55 on both sides, which leaves us to 15.2 = b. However, don't forget the units, which the answer (length of base) should be 15.2 in.^2.
The maximum possible area would have a length of 24 feet and width of 12 feet.
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more numbers and variables.
An independent variable is a variable that does not depend on other variables while a dependent variable is a variable that depends on other variables.
Let x represent the length and y represent the width, hence:
Since beth has 48 ft fencing and cover 3 sides, hence:
x + 2y = 48
x = 48 - 2y (1)
Also:
Area (A) = xy
A = (48 - 2y)y
A = 48y - 2y²
The maximum area is at A' = 0, hence:
A' = 48 - 4y
48 - 4y = 0
y = 12 feet
x = 48 - 2(12) = 24
The maximum possible area would have a length of 24 feet and width of 12 feet.
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Answer:
Prime numbers are numbers that cannot be divided into further whole numbers. You cannot divide 19 and 13 because 13 and 19 are already prime numbers.
Step-by-step explanation:
Answer:
A. A(n) = 150 • (0.74)^n–1 ; 33.29 cm
Step-by-step explanation:
This is a geometric sequence.
a%5B1%5D=1.5m=150cm, r=0.74
The formula is
a%5Bn%5D=a%5B1%5Dr%5E%28n-1%29
Just substitute a1 = 150cm and r = 0.74
a%5Bn%5D=150%280.74%29%5E%28n-1%29
That's the rule.
For the second part, substitute n = 6
cm.
Answer: A= 460 mm2
Step-by-step explanation:
Hi, since the circumference formula is :
C = 2 π r
Where r is the radius, we can solve the formula for the radius replacing with the value given:
76 =2 π r
76 / (2 π) = r
r = 12.1 mm
Now , we have to apply the formula for the area of a circle.
A = π r^2
A = π (12.1)^2
A= 459.96 mm2= 460 mm2 (rounded to the nearest tenth, since .9 is higher than .5)
Feel free to ask for more if needed or if you did not understand something.
