Answer:
Step-by-step explanation:
From the given information, we can compute the table showing the summarized statistics of the two alloys A & B:
Alloy A Alloy B
Sample mean 
Equal standard deviation 
Sample size 
Mean of the sampling distribution is :
Standard deviation of sampling distribution:
Hypothesis testing.
Null hypothesis: 
Alternative hypothesis: 
The required probability is:
![P(\overline X_A - \overline X_B>4|\mu_A - \mu_B) = P\Big (\dfrac{(\overline X_A - \overline X_B)-\mu_{X_A-X_B}}{\sigma_{\overline x_A -\overline x_B}} > \dfrac{4 - \mu_{X_A-\overline X_B}}{\sigma _{\overline x_A - \overline X_B}} \Big) \\ \\ = P \Big( z > \dfrac{4-0}{1.2909}\Big) \\ \\ = P(z \ge 3.10)\\ \\ = 1 - P(z < 3.10) \\ \\ \text{Using EXCEL Function:} \\ \\ = 1 - [NORMDIST(3.10)] \\ \\ = 1- 0.999032 \\ \\ 0.000968 \\ \\ \simeq 0.0010](https://tex.z-dn.net/?f=P%28%5Coverline%20X_A%20-%20%5Coverline%20X_B%3E4%7C%5Cmu_A%20-%20%5Cmu_B%29%20%3D%20P%5CBig%20%28%5Cdfrac%7B%28%5Coverline%20X_A%20-%20%5Coverline%20X_B%29-%5Cmu_%7BX_A-X_B%7D%7D%7B%5Csigma_%7B%5Coverline%20x_A%20-%5Coverline%20x_B%7D%7D%20%3E%20%5Cdfrac%7B4%20-%20%5Cmu_%7BX_A-%5Coverline%20X_B%7D%7D%7B%5Csigma%20_%7B%5Coverline%20x_A%20-%20%5Coverline%20X_B%7D%7D%20%20%20%5CBig%29%20%5C%5C%20%5C%5C%20%3D%20P%20%5CBig%28%20z%20%3E%20%5Cdfrac%7B4-0%7D%7B1.2909%7D%5CBig%29%20%5C%5C%20%5C%5C%20%3D%20P%28z%20%5Cge%203.10%29%5C%5C%20%5C%5C%20%3D%201%20-%20P%28z%20%3C%203.10%29%20%5C%5C%20%5C%5C%20%5Ctext%7BUsing%20EXCEL%20Function%3A%7D%20%5C%5C%20%5C%5C%20%20%3D%201%20-%20%5BNORMDIST%283.10%29%5D%20%20%5C%5C%20%5C%5C%20%3D%201-%200.999032%20%5C%5C%20%5C%5C%200.000968%20%5C%5C%20%5C%5C%20%5Csimeq%20%200.0010)
This implies that a minimal chance of probability shows that the difference of 4 is not likely, provided that the two population means are the same.
b)
Since the P-value is very small which is lower than any level of significance.
Then, we reject 
and conclude that there is enough evidence to fully support alloy A.
Let me guess the answer is 8
Answer: The treatments in the study are strength training, flexibility training, aerobics, and jogging.
Step-by-step explanation:
A correct description of a feature of the study is that the treatments in the study are strength training, flexibility training, aerobics, and jogging.
It should be noted that the study has no replication. Also, the experimental units are the 40 members that participated.
Therefore, the correct option is D.
Looking at the graph of this exponential function, we can see the following behaviors:
When the value of x increases, the value of f(x) decreases, approaching the value y = 1 when x tends to positive infinity.
When the value of x decreases, the value of f(x) increases, going towards positive infinity.
Therefore the answers are:
As x decreases without bound, the graph of f(x):
increases without bound
As x increases without bound, the graph of f(x):
approaches y=1
Answer:
Hypothesis: If I am at least 16 years and 6 months old
Conclusion: Then I am able to get a provisional license
I hope this helps!
