Answer:
∠BDC=50°
Step-by-step explanation:
∠BDC=∠A[angles at the same segment)
∠A= 180-(65+65)=180-130= 50°
so, ∠BDC=50°
<em>MARK ME BRAINLIEST</em>
Could you explain a bit more please
<span>1.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-2);y=-x-2
D.y=-x
2.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-1);y=-3/2x-6
C.y=-3/2x+2
3.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (4,2);x=-3
D.y=4
4.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (-2,3);y=1/2x-1
B.y=-2x-1
5.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (5,0);y+1=2(x-3)
D.y=-1/2x+5/2</span>
2(3)(2) + 2(4)(3) + 2(4)(2)
2(6) + 2(12) + 2(8)
12 + 24 + 16
52
Hope this helps!
Answer:
Sohan has read more pages and Sonali was more faster
