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3 years ago

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Given the equation −4square root of x minus 3 = -12, solve for x and identify if it is an extraneous solution. x = 0, solution i

s extraneous x = 0, solution is not extraneous x = 12, solution is extraneous x = 12, solution is not extraneous

1 answer:

soldier1979 [14.2K]3 years ago

4 0

Answer:

square root of 81

square root of 1000

square root of 34

square root of 169

Step-by-step explanation:

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tamaranim1 [39]

Answer:

(3, 0) and (5, 0)

Step-by-step explanation:

we have

$y=x^{2}-8x+15$

we know that

The x-intercepts are the values of x when the value of y is equal to zero

so

For y=0

$x^{2}-8x+15=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2}-8x+15=0$

so

$a=1\\b=-8\\c=15$

substitute in the formula

$x=\frac{-(-8)\pm\sqrt{-8^{2}-4(1)(15)}} {2(1)}$

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$x=\frac{8\pm2} {2}$

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$x=\frac{8-2} {2}=3$

so

x=3, x=5

therefore

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