Question

Find the indicated values, where g(t)= t^2 - t and f(x)= 1+x

Answer 1

Answer:

Option b is correct

g(f(3)-2f(1))  =0

Step-by-step explanation:

Given the functions:

$g(t) = t^2-t$

and

$f(x) = 1+x$

We have to find g(f(3)-2f(1)) .

At x = 3

$f(3) = 1+3 = 4$

at x = 1

$f(1) = 1+1= 2$

then;

g(f(3)-2f(1)) = $g(4-2(2)) = g(4-4) = g(0)$

then;

$g(f(3)-2f(1)) = 0^2-0 = 0$

Therefore, the indicated value of $g(f(3)-2f(1))$ is , 0

Answer 2

Your answer would be B