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AVprozaik [17]
4 years ago
12

Helping people keep track on things is the purpose of_____ A database B table C query D form​

Computers and Technology
1 answer:
Kitty [74]4 years ago
8 0

Answer:

A) database

Explanation:

A database is used by people to help keep track on things

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RUDIKE [14]

Answer:

Shows the programming checking if num1 is greater than num2

Explanation:

So num1 and num2 are inputs

for you to code this you would need to put

num1=int(input("What is your first number? ))

and the same for num2 except change num1 for num 2 and first for second

When the input is completed, the computer will check if num 1 is greater than num2

it will do this by using a code something like:

if num1>num2:

    Print("Your first input was greater than your second")

But in this example if it greater it just ends

But if it was less than you would put

if num1>num2:

    Print("Your first input was greater than your second")

elif num1<num2:

    Print("Your first input is less than your second")

So basically this code shows the computer checking if one number is greater than the other or not

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3 years ago
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Masja [62]
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Which payment type is best if you are trying to stick to a budget?
nignag [31]

Answer:

debit card, credit cards usually make people overspend, and cash advance is a bad fee (like $10 minimum usually), and loans have interest

Explanation:

6 0
3 years ago
1. Print out the string length of s1 2. Loop through characters in s2 with charAt() and display reversed string 3. Compare s2, s
konstantin123 [22]

Answer:

See explaination

Explanation:

public class StringLab9 {

public static void main(String args[]) {

char charArray[] = { 'C', 'O', 'S', 'C', ' ', '3', '3', '1', '7', ' ', 'O', 'O', ' ', 'C', 'l', 'a', 's', 's' };

String s1 = new String("Objected oriented programming language!");

String s2 = "COSC 3317 OO class class";

String s3 = new String(charArray);

// To do 1: print out the string length of s1

System.out.println(s1.length());

// To do 2: loop through characters in s2 with charAt and display reversed

// string

for (int i = s2.length() - 1; i >= 0; --i)

System.out.print(s2.charAt(i));

System.out.println();

// To do 3: compare s2, s3 with compareTo(), print out which string (s2 or s3)

// is

// greater than which string (s2 or s3), or equal, print the result out

if (s2.compareTo(s3) == 0)

System.out.println("They are equal");

else if (s2.compareTo(s3) > 0)

System.out.println("s2 is greater");

else

System.out.println("s3 is greater");

// To do 4: Use the regionMatches to compare s2 and s3 with case sensitivity of

// the first 8 characters.

// and print out the result (match or not) .

if (s2.substring(0, 8).compareTo(s3.substring(0, 8)) == 0)

System.out.println("They matched");

else

System.out.println("They DONT match");

// To do 5: Find the location of the first character 'g' in s1, print it out

int i;

for (i = 0; i < s2.length(); ++i)

if(s2.charAt(i)=='g')

break;

System.out.println("'g' is present at index " + i);

// To do 6: Find the last location of the substring "class" from s2, print it

// out

int index = 0, ans = 0;

String test = s2;

while (index != -1) {

ans = ans + index;

index = test.indexOf("class");

test = test.substring(index + 1, test.length());

}

System.out.println("Last location of class in s2 is: " + (ans + 1));

// To do 7: Extract a substring from index 4 up to, but not including 8 from

// s3, print it out

System.out.println(s3.substring(4, 8));

} // end main

} // end class StringLab9

7 0
3 years ago
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