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BaLLatris [955]

3 years ago

5

Compare and contrast trapezoids and parallelograms

1 answer:

gulaghasi [49]3 years ago

3 0

I hope this chart is helpful

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Please help! i'm confused!<br> Find the area of a kites with diagonals 9in and 12in.

kolbaska11 [484]

Notice the picture
the rhombus, or kite, is really just 4 triangles
all sides are the same lenght in a rhombus,

thus, find the area of all of the triangles,
and you already have two sides given,
and then, add them up

or just find the length of one, and multiply times 4 :)

recall, area of a triangle = 1/2 bh

8 0

3 years ago

Which solid has a greater volume? O A. Figure A 48 B. Figure B O C. they are equal A 2 O D. need more information

MatroZZZ [7]

9514 1404 393

Answer:

B. Figure B

Step-by-step explanation:

The figure is difficult to read. We assume the height of the pyramid is 9, and the radius of the cylinder is 1.

The pyramid volume is ...

V = 1/3Bh

V = 1/3(4²)(9) = 48 . . . cubic units

__

The cylinder volume is ...

V = πr²h

V = π(1²)(48) = 48π . . . cubic units

The cylinder has π times as much volume as the pyramid. Figure B is larger.

_____

<em>Additional comment</em>

If the diameter (not the radius) of the cylinder is 1 unit, then its volume is 12π cubic units and the pyramid has more volume.

7 0

3 years ago

12. On a table there were 16 dimes and quarters. The value of the coins was

7nadin3 [17]

6 quarters and 10 dimes

6 0

3 years ago

How do you do 3(4y-7)=15y+6

cestrela7 [59]

Answer:

y = 27/7

Step-by-step explanation:

Perform the indicated multiplication:

3(4y-7)=15y+6 becomes:

12y - 21 = 5y + 6

Combining like terms, we get:

7y = 27, so that y = 27/7

7 0

3 years ago

Pleaseeeeeee help mee

BlackZzzverrR [31]

Answer:

The solution of the given trigonometric equation

$x = \frac{\pi }{6}$

Step-by-step explanation:

<u><em>Step(i):</em></u>-

Given

$cos( 3x - \frac{\pi }{3} ) = \frac{\sqrt{3} }{2}$

$cos( 3x - \frac{\pi }{3} ) = cos (\frac{\pi }{6} )$

$3x - \frac{\pi }{3} = \frac{\pi }{6}$

$3x - \frac{\pi }{3 } + \frac{\pi }{3} = \frac{\pi }{6} + \frac{\pi }{3}$

$3x = \frac{2\pi +\pi }{6} = \frac{3\pi }{6} = \frac{\pi }{2}$

$x = \frac{\pi }{6}$

<u><em>Step(ii)</em></u>:-

The solution of the given trigonometric equation

$x = \frac{\pi }{6}$

<u><em>verification </em></u>:-

$cos( 3x - \frac{\pi }{3} ) = \frac{\sqrt{3} }{2}$

put $x = \frac{\pi }{6}$

$cos( 3(\frac{\pi }{6}) - \frac{\pi }{3} ) = \frac{\sqrt{3} }{2}$

$cos (\frac{\pi }{6} ) = \frac{\sqrt{3} }{2} \\\\\frac{\sqrt{3} }{2} = \frac{\sqrt{3} }{2}$

Both are equal

∴The solution of the given trigonometric equation

$x = \frac{\pi }{6}$

4 0

2 years ago