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Anna35 [415]
3 years ago
9

7.

Mathematics
1 answer:
aivan3 [116]3 years ago
6 0

Answer:

non-linear:  C, E, F

Step-by-step explanation:

Choices A, B, D are linear functions, so the rest are non-linear:  C, E, F

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Show the work on 6 divided by 5,406
fenix001 [56]
I think it's the 0.0011098779
5 0
3 years ago
HELP PLEASE <br> (Look at the picture)
aksik [14]

Answer:

D is correct (I think).

Step-by-step explanation:

A and C are completely invalid, as A is a linear function and C does not go up in intervals of 25.

Answer C is a linear function and is represented by y=x+1, but there are potential other reasons that it could be considered a linear function.

Answer D cannot be solved by y=mx+b because it is an exponential function.

3 0
2 years ago
A 500500-gallon tank initially contains 200200 gallons of brine containing 100100 pounds of dissolved salt. brine containing 11
mixer [17]
Let A(t) denote the amount of salt in the tank at time t. We're given that the tank initially holds A(0)=100 lbs of salt.

The rate at which salt flows in and out of the tank is given by the relation

\dfrac{\mathrm dA}{\mathrm dt}=\underbrace{\dfrac{11\text{ lb}}{1\text{ gal}}\times\dfrac{44\text{ gal}}{1\text{ min}}}_{\text{rate in}}-\underbrace{\dfrac{A(t)}{200+(44-11)t}\times\dfrac{11\text{ gal}}{1\text{ min}}}_{\text{rate out}}
\implies A'(t)+\dfrac{11}{200+33t}A(t)=484

Find the integrating factor:

\mu(t)=\exp\left(\displaystyle\int\frac{11}{200+33t}\,\mathrm dt\right)=(200+33t)^{1/3}

Distribute \mu(t) along both sides of the ODE:

(200+33t)^{1/3}A'(t)+11(200+33t)^{-2/3}A(t)=484(200+33t)^{-1/3}
\bigg((200+33t)^{1/3}A(t)\bigg)'=484(200+33t)^{-1/3}
A(t)=484\displaystyle\int(200+33t)^{-1/3}\,\mathrm dt
A(t)=22(200+33t)^{2/3}+C

Since A(0)=100, we get

100=22(200)^{2/3}+C\implies C\approx-652.39

so that the particular solution for A(t) is

A(t)=22(200+33t)^{2/3}-652.39

The tank becomes full when the volume of solution in the tank at time t is the same as the total volume of the tank:

200+(44-11)t=500\implies 33t=300\implies t\approx9.09

at which point the amount of salt in the solution would be

A(9.09)\approx733.47\text{ lb}
4 0
3 years ago
24÷30 help plaese now i am desparate thank you
Nataliya [291]

Answer:

Step-by-step explanation:

the answer to your problem is 0.8

8 0
3 years ago
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Answer:

<h2>≠</h2>

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