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kotykmax [81]
3 years ago
9

To place an ad in the Harrisonburg newspaper it cost $100 for each 1/8 of a page used. How much would an advertisement cost if i

t took up 3/4 of a page
Mathematics
2 answers:
meriva3 years ago
8 0

Answer: the cost of an advertisement that takes up 3/4 of a page is $600

Step-by-step explanation:

To place an advertisement in the Harrisonburg newspaper it cost $100 for each 1/8 of a page used. This means that the cost of placing an advertisement of 1 page in the Harrisonburg newspaper would be

1/8 × 100 = $800

Therefore, if an advertisement takes up 3/4 of a page, it means that cost of the advertisement would be

3/4 × 800 = 0.75 × 800 = $600

larisa86 [58]3 years ago
3 0

Answer:

It would cost <u>$600</u> for an advertisement of  \frac{3}{4}  of a page.

Step-by-step explanation:

Given:

To place an ad in the Harrisonburg newspaper it cost $100 for each 1/8 of a page used.

Now, to find the cost of an advertisement 3/4 of a page.

So, to get the cost we use unitary method:

<em>If,  </em>\frac{1}{8}<em> of a page used cost = $100.</em>

<em>Then, 1 page used cost = </em>100\div \frac{1}{8}<em> = </em>\$800.<em />

<em>Thus,  </em>\frac{3}{4}<em>  of a page used cost</em> = 800\times \frac{3}{4} =\frac{2400}{4}=\$600.

Therefore, it would cost $600 for an advertisement of  \frac{3}{4}  of a page.

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What is the fourth term in the binomial expansion (a+b)^6)
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Answer:

20a^3b^3

Step-by-step explanation:

<u>Binomial Series</u>

(a+b)^n=a^n+\dfrac{n!}{1!(n-1)!}a^{n-1}b+\dfrac{n!}{2!(n-2)!}a^{n-2}b^2+...+\dfrac{n!}{r!(n-r)!}a^{n-r}b^r+...+b^n

<u>Factorial</u> is denoted by an exclamation mark "!" placed after the number. It means to multiply all whole numbers from the given number down to 1.

Example:  4! = 4 × 3 × 2 × 1

Therefore, the fourth term in the binomial expansion (a + b)⁶ is:

\implies \dfrac{n!}{3!(n-3)!}a^{n-3}b^3

\implies \dfrac{6!}{3!(6-3)!}a^{6-3}b^3

\implies \dfrac{6!}{3!3!}a^{3}b^3

\implies \left(\dfrac{6 \times 5 \times 4 \times \diagup\!\!\!\!3 \times \diagup\!\!\!\!2 \times \diagup\!\!\!\!1}{3 \times 2 \times 1 \times \diagup\!\!\!\!3 \times \diagup\!\!\!\!2 \times \diagup\!\!\!\!1}\right)a^{3}b^3

\implies \left(\dfrac{120}{6}\right)a^{3}b^3

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2 years ago
Round 128.59943 to 3 decimal places
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To 3 decimal places.

128.59943

Count three places to the right after the decimal point. The third digit is 9, and the fourth is 4. Since the 4th is not up to 5, we leave the 9 that way and so we can not round up the 9 to 10.

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Thanks.
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The actual width ( w) of a regulation soccer field is 90 meters (m), and the actual length is 120 meters (m). A coach has drawn
vladimir2022 [97]

Answer:

Proportion states that the two equal ratios or fractions are equal.

Use conversion:

1 m = 100 cm

As per the statement:

The actual width ( w) of a regulation soccer field is 90 meters (m), and the actual length is 120 meters (m

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It is also given that:

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Divide both sides by 120 we get;

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Or

\text{Drawing width} =13.5 cm

Therefore, the other side of the drawing width is 13.5 cm

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