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creativ13 [48]
3 years ago
14

kest kuy is offering a sale on its laptop computers with a 20 percent discount off its original price. there is 8% sales tax add

ed to the discounted price to get the final price of the computer. if x is the original price and y is the final price, write an equation to determine the final price based upon the original price.
Mathematics
1 answer:
iVinArrow [24]3 years ago
6 0

Answer:

y = 0.88x

Step-by-step explanation:

Given

Discount = 20\%

Sales\ Tax = 8\%

Required

Determine the final price

First, we need to determine the sales price after the discount.

Discount = 20\% * x

Discount = 0.20 * x

Discount = 0.20x

Sales\ Price = x - Discount

Sales\ Price = x - 0.20x

Sales\ Price = 0.80x

Next, is to determine the sales tax.

Sales\ Tax = 8\% * x

Sales\ Tax = 0.08 * x

Sales\ Tax = 0.08x

Final Price, y is then calculated as thus:

y = Sales\ Price + Sales\ Tax

y = 0.80x + 0.08x

y = 0.88x

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The time needed to complete a final examination in a particular college course is normally distributed with a mean of 77 minutes
Komok [63]

Answer:

a. The probability of completing the exam in one hour or less is 0.0783

b. The probability that student will complete the exam in more than 60 minutes but less than 75 minutes is 0.3555

c. The number of students will be unable to complete the exam in the allotted time is 8

Step-by-step explanation:

a. According to the given we have the following:

The time for completing the final exam in a particular college is distributed normally with mean (μ) is 77 minutes and standard deviation (σ) is 12 minutes

Hence, For X = 60, the Z- scores is obtained as follows:

Z=  X−μ /σ

Z=60−77 /12

Z=−1.4167

Using the standard normal table, the probability P(Z≤−1.4167) is approximately 0.0783.

P(Z≤−1.4167)=0.0783

Therefore, The probability of completing the exam in one hour or less is 0.0783.

b. In this case For X = 75, the Z- scores is obtained as follows:

Z=  X−μ /σ

Z=75−77 /12

Z=−0.1667

Using the standard normal table, the probability P(Z≤−0.1667) is approximately 0.4338.

Therefore, The probability that student will complete the exam in more than 60 minutes but less than 75 minutes is obtained as follows:

P(60<X<75)=P(Z≤−0.1667)−P(Z≤−1.4167)

=0.4338−0.0783

=0.3555

​

Therefore, The probability that student will complete the exam in more than 60 minutes but less than 75 minutes is 0.3555

c. In order to compute  how many students you expect will be unable to complete the exam in the allotted time we have to first compute the Z−score of the critical value (X=90) as follows:

Z=  X−μ /σ

Z=90−77 /12

Z​=1.0833

UsING the standard normal table, the probability P(Z≤1.0833) is approximately 0.8599.

Therefore P(Z>1.0833)=1−P(Z≤1.0833)

=1−0.8599

=0.1401

​

Therefore, The number of students will be unable to complete the exam in the allotted time is= 60×0.1401=8.406

The number of students will be unable to complete the exam in the allotted time is 8

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2 years ago
Y is inversely proportional to x<br> when y=7 and x=9<br> work out the equation connecting y and x
yan [13]

Answer:

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Step-by-step explanation:

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PIT_PIT [208]

Answer:

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Step-by-step explanation:

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