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3 years ago

Round 128.59943 to 3 decimal places

2 answers:

7 0

To 3 decimal places.

128.59943

Count three places to the right after the decimal point. The third digit is 9, and the fourth is 4. Since the 4th is not up to 5, we leave the 9 that way and so we can not round up the 9 to 10.

So it becomes = 128.599

Thanks.

Virty [35]3 years ago

3 0

128.59943

So we need to round this to 3 decimal places. So, in 128.59943, .59943 is closer to .599 than .600

So , lets give it 128.599

So, the answer is 128.599.

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The family must drive 430 miles to get to Pensacola Colorado

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Find the surface area of the figure. Round to the nearest tenth if possible.

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2 years ago

If the cost of 6 sandwiches and 4 drinks is $53 how much is one drink

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2 years ago

Read 2 more answers

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2 years ago

Read 2 more answers

If we sample from a small finite population without replacement, the binomial distribution should not be used because the event

seropon [69]

Answer:

5/4324 = 0.001156337

Step-by-step explanation:

To better understand the hyper-geometric distribution consider the following example:

There are 100 senators in the US Congress, and suppose 60 of them are republicans so 100 - 60 = 40 are democrats).

We extract a random sample of 30 senators and we want to answer this question:

What is the probability that 10 senators in the sample are republicans (and of course, 30 - 10 = 20 democrats)?

The answer using the h-g distribution is:

$\large \frac{\binom{60}{10}\binom{100-60}{30-10}}{\binom{100}{30}}=\frac{\binom{60}{10}\binom{40}{20}}{\binom{100}{30}}$

Now, imagine there are 56 senators (56 lottery numbers), 6 are republicans (6 winning numbers and 50 losers), we extract a sample of 6 senators (the bettor selects 6 numbers). What is the probability that 4 senators are republicans? (What is the probability that 4 numbers are winners?).

<em>As we see, the situation is exactly the same,</em> but changing the numbers. So the answer would be

$\large \frac{\binom{6}{4}\binom{56-6}{6-4}}{\binom{56}{6}}=\frac{\binom{6}{4}\binom{50}{2}}{\binom{56}{6}}$

Now compute each combination separately:

$\large \binom{6}{4}=\frac{6!}{4!2!}=15\\\\\binom{50}{2}=\frac{50!}{2!48!}=1225\\\\\binom{50}{6}=\frac{50!}{6!44!}=15890700$

and now replace the values:

$\large \frac{\binom{6}{4}\binom{50}{2}}{\binom{56}{6}}=\frac{15*1225}{15890700}=\frac{18375}{15890700}=\frac{5}{4324}$

and that is it.

If the decimal expression is preferred then divide the fractions to get 0.001156337

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2 years ago