Question

Please Help ASAP!! 20 points!!

Answer 1

Answer:

$\cos ^{-1}(\frac{6.3}{9.8})$

$\sin^{-1} (\frac{7.5}{9.8})$

Step-by-step explanation:

Recall and use the mnemonics SOH to obtain;

$\sin(\angle ABC) =\frac{Opposite}{Hypotenuse}$

This implies that;

$\sin(m \angle ABC) =\frac{7.5}{9.8}$

Take the inverse sine of both sides to get;

$m\angle ABC =\sin^{-1} (\frac{7.5}{9.8})$

Also,

$\cos (m\angle ABC)=\frac{Adjacent}{Hypotenuse}$

$\cos (m\angle ABC)=\frac{6.3}{9.8}$

$\Rightarrow m\angle ABC=\cos ^{-1}(\frac{6.3}{9.8})$