Answer:
21 / 143
Step-by-step explanation:
Given that:
Number of Eastern conference reps = 8
Number of western conference rep = 7
Probability of selecting 3 from Eastern reps and 2 from western reps
Probability = required outcome / Total possible outcomes
Total possible outcomes:
selection to be made = 3+ 2 = 5
Total Number of players = 8 +7 = 15
Total possible outcomes
Using combination formula :
nCr = n! / (n-r)!r!
15C5 = 15! / 10!5! = (15 * 14 * 13 * 12 * 11) / (5*4'3*2*1) = 360360 / 120 = 3003
Total possible outcomes = 3003
Required outcome :
8C3 * 7C2
8C3 = 56 ; 7C2 = 21
8C3 * 7C2 = 56 * 21 = 1176
required outcome / Total possible outcomes
= 1176 / 3003
= 21 / 143
Using the sum (addition) and two 2-digit addends, 12 + 34 can be answered without regrouping.
Answer:
68% Confidence interval = [4.5752, 4.5848]
95% Confidence interval = [4.5688, 4.5918]
Step-by-step explanation:
Sample mean (X) = 4.580
Sample Standard Deviation (S) = 0.01065
Sample size (n) = 6
for alpha/2 0.84 = 1.1037
for alpha/2 0.975 = 2.5706
68% Confidence interval = ![[x-T_{(5)}\frac{S}{\sqrt{n}}, x+T_{(5)]\frac{S}{\sqrt{n}}]](https://tex.z-dn.net/?f=%5Bx-T_%7B%285%29%7D%5Cfrac%7BS%7D%7B%5Csqrt%7Bn%7D%7D%2C%20x%2BT_%7B%285%29%5D%5Cfrac%7BS%7D%7B%5Csqrt%7Bn%7D%7D%5D)
= [4.5752, 4.5848]
95% Confidence interval = ![[x-T_{(5)}\frac{S}{\sqrt{n}}, x+T_{(5)}\frac{S}{\sqrt{n}}]](https://tex.z-dn.net/?f=%5Bx-T_%7B%285%29%7D%5Cfrac%7BS%7D%7B%5Csqrt%7Bn%7D%7D%2C%20x%2BT_%7B%285%29%7D%5Cfrac%7BS%7D%7B%5Csqrt%7Bn%7D%7D%5D)
= [4.5688, 4.5918]
