9514 1404 393
Answer:
arc AC = 63°
Step-by-step explanation:
Arc BC is twice the measure of inscribed angle BAC, so is ...
arc AC = 2×89° = 178°
The remaining arc of the circle is the difference between 360° and the sum of the other two.
arc AC = 360° -119° -178°
arc AC = 63°
So if it has to be simplified, there is only one answer if all of it is positive but it has a solution to do with minus numbers which is -2 (-x-2)
Answer:
x = 2
Step-by-step explanation:
The product of distances from the intersection of secants to the near and far intersections with the circle are the same. For a tangent, the near and far points of intersection with the circle are the same. This relation tells us ...
(2√3)(2√3) = x(x +4)
12 = x² +4x
16 = x² +4x +4 . . . . . add the square of half the x-coefficient to complete the square
4² = (x +2)² . . . . . . . . write as squares
4 = x +2 . . . . . . . . . . positive square root
2 = x . . . . . . . . . . . . . subtract 2
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<em>Alternate solution</em>
If you believe x to be an integer, you can look for factors of 12 that differ by 4.
12 = 1×12 = 2×6 = 3×4
The factors 2 and 6 differ by 4, so x=2 and x+4=6.
We have been given that a right △ABC is inscribed in circle k(O, r).
m∠C = 90°, AC = 18 cm, m∠B = 30°. We are asked to find the radius of the circle.
First of all, we will draw a diagram that represent the given scenario.
We can see from the attached file that AB is diameter of circle O and it a hypotenuse of triangle ABC.
We will use sine to find side AB.
Wee know that radius is half the diameter, so radius of given circle would be half of the 36 that is 
.
Therefore, the radius of given circle would be 18 cm.
