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3 years ago

To multiply or divide a number by 10,000, how many places should you move the decimal point? 1. four

Mathematics

2 answers:

Llana [10]3 years ago

7 0

The answer is either number or two I suppose.

suter [353]3 years ago

4 0

You should move the decimal point four times. One time for each consecutive zero.

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ozzi

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2 years ago

Three times one number added to five times another number is 54. The second number is two less than the first. Use a system of e

worty [1.4K]

Answer:

8 and 6

Step-by-step explanation:

If you use x for the first number, and y for the second, you get equations of 3x+5y=54 and x-2=y.

You can substitute the second equation into the first one to solve it. This gives 3x+5(x-2)=54.

The brackets can be expanded to 3x+5x-10=54. Collecting like terms makes it 8x-10=54.

Next, we add 10 to both sides. This gives 8x=64.

From there, we isolate the x by dividing both sides by 8, giving x=8.

To work out the second number, we can sub 8 for x in either equation (I'm using the second one as it's simpler).

This comes to y=8-2, therefore y=6.

**This content is simultaneous equations, which you may wish to revise. I'm always happy to help!

3 0

2 years ago

Michelle bought five packs of crayons for 13.75. what is the cost of a pack ,in dollars, if all the packs cost the same

Schach [20]

Answer:

2.75

Step-by-step explanation:

Divide 13.75 by five.

5 0

2 years ago

Help please i don’t know how to do it

Norma-Jean [14]

Answer:

Step-by-step explanation:

$\frac{dy}{dx}=x^{2}(y-1)\\\frac{1}{y-1} \text{ } dy=x^{2} \text{ } dx\\\int \frac{1}{y-1} \text{ } dy=\int x^{2} \text{ } dx\\\ln|y-1|=\frac{x^{3}}{3}+C\\$

From the initial condition,

$\ln|3-1|=\frac{0^{3}}{3}+C\\\ln 2=C$

So we have that $\ln |y-1|=\frac{x^{3}}{3}+\ln 2\\e^{\frac{x^{3}}{3}+\ln 2}=y-1\\2e^{\frac{x^{3}}{3}}=y-1\\y=2e^{\frac{x^{3}}{3}}+1$

4 0

2 years ago

We’re is the blue dot on the number line?

BartSMP [9]

Answer:

thank u !! -4.9

7 0

2 years ago

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