Question

the number of bacteria in a culture is growing at a rate of 1500e^(3t/4) per unit of time t. at t=0, the number of bacteria present was 2000. find the number present at t=4.

Answer 1

At t=0,
P=2000 2000=2000e^0+C
C=0

P(t)=2000e^{3t/4}
P(4)=2000e^3
P(4)=40171.1

Answer 2

Quarter 200 of per unit =3t)4^