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3 years ago

Solve the system: 2x+3y=6 and x=-2y+3. I need help

Mathematics

1 answer:

Alex Ar [27]3 years ago

3 0

Answer:

$\large\boxed{x=3,\ y=0\to(3,\ 0)}$

Step-by-step explanation:

$\left\{\begin{array}{ccc}2x+3y=6&(1)\\x=-2y+3&(2)\end{array}\right\\\\\text{Substitute (2) to (1):}\\\\2(-2y+3)+3y=6\qquad\text{use distributive property}\\\\(2)(-2y)+(2)(3)+3y=6\\\\-4y+6+3y=6\qquad\text{subtract 6 from both sides}\\\\-y=0\to\boxed{y=0}\\\\\text{Put the value of y to (2):}\\\\x=-2(0)+3\\\\x=0+3\\\\\boxed{x=3}$

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3 years ago

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3 years ago

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Like :

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Or multiply by any number,

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3 years ago

What is the graph of the function f(x) = the quantity of x plus 2, all over x minus 3

Andrej [43]

Answer:

Step-by-step explanation:

The given function is $f(x)=\frac{x+2}{x-3}$ and we need to graph it.

In order to graph this function, we'll find below things:

Horizontal asymptote:

Since the degree of both numerator and denominator is same. Hence, the horizontal asymptote is the ratio of leading coefficient of numerator to the leading coefficient of denominator.

Horizontal asymptote is y = 1/1 = 1

Vertical asymptote:

Vertical asymptote occurs where the denominator is zero.

$x-3=0\\x=3$