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galina1969 [7]
2 years ago
8

Plz help me well mark brainliest if correct....????

Mathematics
2 answers:
sattari [20]2 years ago
8 0

Answer:

i think 18 msy be

Step-by-step explanation:

12345 [234]2 years ago
5 0

Answer:

C

Step-by-step explanation:

18 boys

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Nadya [2.5K]

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8+8+9+9.. so the answer is 34 yards.

Step-by-step explanation:

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If you are driving on the freeway at 55 mph and you travel for 5 hours, how far will you have gone?
alina1380 [7]
275 because 55 times 5 equals 275 ! Hope this helps
8 0
3 years ago
Read 2 more answers
URGENT!!!! FIRST ANSWER GETS BRAINLIEST!!!!!
DerKrebs [107]

Answer:

The 4th picture will be the correct one.

Step-by-step explanation:

The first picture shows the graph of f(x) and in the options there are pictures of graph of g(x) = f(x) -1

So, it is clear from the equation of the functions that the graph of f(x) and g(x) will be similar but the the y value in g(x) will be 1 less than the y value in f(x) corresponding to a certain x value.

So, the graph will translate down by 1 unit.

Therefore, the 4th picture will be the correct one.

8 0
3 years ago
I need to know the answers for 1-6 please.
telo118 [61]

1: $1.5

2: $10.5

3: $.40

4: $33

5: $.80

6: $10

8 0
3 years ago
Find the equation of the line that is perpendicular to the line y = (-1/3)x -1 and passes through the point (1, 5)?
Anit [1.1K]

bearing in mind that perpendicular lines have negative reciprocal slopes, so


\bf \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}~\hspace{10em}\stackrel{slope}{y=\stackrel{\downarrow }{-\cfrac{1}{3}}x-1} \\\\[-0.35em] ~\dotfill


\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{-\cfrac{1}{3}}\qquad \qquad \qquad \stackrel{reciprocal}{-\cfrac{3}{1}}\qquad \stackrel{negative~reciprocal}{+\cfrac{3}{1}\implies 3}}


so we're really looking for a line whose slope is 3 and runs through (1,5)


\bf (\stackrel{x_1}{1}~,~\stackrel{y_1}{5})~\hspace{10em} slope = m\implies 3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-5=3(x-1) \\\\\\ y-5=3x-3\implies y=3x+2

4 0
3 years ago
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