Step-by-step explanation:
since in a triangle each side must be shorter than the sum of the other 2 sides (otherwise the end points cannot connect, and there is no triangle), the necessary inequality condition must be
side < 1 + 2 = 3
so,
side < 3
for a lower limit let's go through the cases
1 < 2 + side (is always true)
2 < 1 + side
1 < side (side must be larger than 1)
and again
side < 1 + 2 = 3
side < 3
so the full restriction for the third side is
1 < side < 3
Answer:
The triangles are congruent by Angle Side Angle congruency statement and the reason is below.
Step-by-step explanation:
Given:
∠ VUW ≅ ∠ XYW
VW ≅ YW
To Prove:
Δ VUW ≅ Δ XYW
Proof:
In Δ VUW and Δ XYW
∠ VUW ≅ ∠ XYW ……….{Given}
VW ≅ YW ............{Given}
∠ VWU ≅ ∠ XWY …………..{Vertically Opposite Angles are equal}
Δ VUW ≅ Δ XYW .….{ By Angle-Side-Angle congruence test}
......Proved
