Next number 3 6 4 8 6 12 10

Mathematics

1 answer:

solniwko [45]3 years ago

6 0

Answer:

Step-by-step explanation:

This sequence follows a pattern of doubling then subtracting by two. The last action was 12 to 10, which is subtracting by two, so the next must be multiplying by 2.

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If line a is perpendicular to line b and the slope of line a is 7 whats the slope of line b

amm1812

Answer:

If a line is perpendicular to another line, that means that the slope is completely opposite that of the original line. The first thing that we do to the slope is we negate the number which means that if we have a slope of $-7$ our slope because $7$ in this step. In our case our slope is $7$ so in this step it becomes $-7$ .

Moving onto the second part which is to get the reciprocal of the number which means that if we have $\frac{1}{2}$ then we would switch it to $2$ . In our case our number is $-7$ so we would make that into a fraction like this $-\frac{1}{7}$ .

In conclusion, our final slope of the perpendicular line is $-\frac{1}{7}$ .

Hope this helps! Let me know if you have any questions

8 0

2 years ago

Read 2 more answers

A credit card company uses these rules to calculate the minimum amount owed: For a bill of less than $100, the entire amount is

Mashutka [201]

Answer:

B. graph B

Step-by-step explanation:

The graphs of A,B,C and D are attached below.

Let x represent the credit amount and y represent the minimum amount due.

For a bill of less than $100, the entire amount is due. That is for 0 ≤ x < $100, y = x

For a bill of at least $100 but less than $500, the minimum due is $100. That is for $100 ≤ x < $500, y = 100

For a bill of at least $500 but less than $1,000, the minimum due is $300. That is for $500 ≤ x < $1000, y = $300

For a bill of $1,000 or more, the minimum due is $500. But the credit limit is $2000. That is For $1000 ≤ x < $2000, y = $500

The graph that shows the minimum amount due for a credit amount of x is graph B

3 0

3 years ago

For the matrices below. Find all (real) eigenvalues. A= [7 9] [0 9]

Jet001 [13]

Answer:

The answer is "9 and 7".

Step-by-step explanation:

Given:

$A=\left[\begin{array}{cc}7&9\\0&9\end{array}\right]$

Using formula:

$|A-\lambda \cdot I|= 0\\\\$

$\to |\left[\begin{array}{cc}7&9\\0&9\end{array}\right]-\lambda \left[\begin{array}{cc}1&0\\0&1\end{array}\right] |=0\\\\\\ \to |\left[\begin{array}{cc}7&9\\0&9\end{array}\right]- \left[\begin{array}{cc}\lambda&0\\0&\lambda\end{array}\right] |=0\\\\\\\to|\left[\begin{array}{cc}7-\lambda &9\\0&9-\lambda\end{array}\right]|=0\\\\\\\to|(7-\lambda)(9-\lambda)|=0\\\\\to (7-\lambda)(9-\lambda)=0\\\\\to 7-\lambda=0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 9-\lambda=0\\\\$