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anyanavicka [17]
3 years ago
13

What is a reflectional symmtery

Mathematics
1 answer:
Andrew [12]3 years ago
5 0
Reflectional symmetry<span> is also called bilateral, line </span>symmetry<span> or mirror </span>symmetry. It occurs when a line is drawn to divide a shape in halves so that each half is areflection<span> of the other. Some shapes or objects, such as circles, squares and triangles, have one or more lines of </span>symmetry<span>. Mark as brainliest if u can thanks</span>
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100 point to the first correct answer
miss Akunina [59]

Answer:

X ~ B(n, p)

Given: X ~ B(2, 5/17)

⇒  n = 2

⇒  p = 5/17

Binomial distribution formula:

\sf P(X = x) = nC_x (1-p)^{(n-x)}p^x

As n = 2, calculate P(X = 0), P(X = 1) and P(X = 2):

\sf P(X = 0) = 2C0 (\frac{12}{17})^{(2-0)}(\frac{5}{17})^0=\dfrac{144}{289}}

\sf P(X = 1) = 2C1 (\frac{12}{17})^{(2-1)}(\frac{5}{17})^1=\dfrac{120}{289}}

\sf P(X = 2) = 2C2 (\frac{12}{17})^{(2-2)}(\frac{5}{17})^2=\dfrac{25}{289}}

**Probability Distribution Table attached**

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2 years ago
Slope for the line perpendicular to the line shown in the graph
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It would be positive 1/3 because if you move to the right one on your bottom point and up 3 it gives you +1/3
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5. Michael makes lemonade using a ratio of 10 cups of water to 1 cup of lemon juice. Which equation could
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Step-by-step explanation:

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3 years ago
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Read 2 more answers
The ideal width of a safety belt strap for a certain automobile is 6 cm. The actual width can vary by at most 0.45 cm. Write an
OlgaM077 [116]

Answer:

|x-6|\le 0.45

x\in [5.55,6.45]

Step-by-step explanation:

<u>Absolute Value Inequality</u>

Assume the actual width of a safety belt strap for a certain automobile is x. We know the ideal width of the strap is 6 cm. This means the variation from the ideal width is x-6.

Note if x is less than 6, then the variation is negative. We usually don't care about the sign of the variation, just the number. That is why we need to use the absolute value function.

The variation (unsigned) from the ideal width is:

|x-6|

The question requires that the variation is at most 0.45 cm. That poses the inequality:

|x-6|\le 0.45

That is the range of acceptable widths. Let's now solve the inequality.

To solve an inequality for an absolute value less than a positive number N, we write:

-0.45\le x-6 \le 0.45

This is a double inequality than can be easily solved by adding 6 to all the sides.

-0.45+6\le x \le 0.45+6

Operating:

5.55\le x \le 6.45

That is the solution in inequality form. Expressing in interval form:

\boxed{x\in [5.55,6.45]}

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3 years ago
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