I would have to say hockey it's like soccer... but with ice
Answer:
So coefficient of kinetic friction will be equal to 0.4081
Explanation:
We have given mass of the block m = 0.5 kg
The spring is compressed by length x = 0.2 m
Spring constant of the sprig k = 100 N/m
Blocks moves a horizontal distance of s = 1 m
Work done in stretching the spring is equal to ![W=\frac{1}{2}kx^2=\frac{1}{2}\times 100\times 0.2^2=2J](https://tex.z-dn.net/?f=W%3D%5Cfrac%7B1%7D%7B2%7Dkx%5E2%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20100%5Ctimes%200.2%5E2%3D2J)
This energy will be equal to kinetic energy of the block
And this kinetic energy must be equal to work done by the frictional force
So ![\mu mg\times s=2](https://tex.z-dn.net/?f=%5Cmu%20mg%5Ctimes%20s%3D2)
![\mu\times 0.5\times 9.8\times 1=2](https://tex.z-dn.net/?f=%5Cmu%5Ctimes%20%200.5%5Ctimes%209.8%5Ctimes%201%3D2)
![\mu =0.4081](https://tex.z-dn.net/?f=%5Cmu%20%3D0.4081)
So coefficient of kinetic friction will be equal to 0.4081
<em>as we know that P=mv .. where m is mass and v is velocity ..this relation shows that momentum has a direct relation with these two quantities .. so when velocity is increased twice
P' = mv
P'=m2v
P' = 2 mv here mv is P so
P'=2P
this shows that momentum will also be doubled by doubling the velocity :)</em>
Answer:
the speed of the cruiser relative to the pursuit ship is 0.3846c
Explanation:
the solution is in the attached Word file