The acceleration of an object depends on the ____________ exerted on it and it's_________ this is to do with newton's seconed la
1 answer:
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Answer:
The distance of first minimum from central maxima is 4.25 m
The spacing between maxima in sound intensity is 8.5 m.
Explanation:
Given that,
Distance D= 15 m
Frequency = 200 Hz
distance between slits a=3 m
We know that,
The width of fringe,
(a). We need to calculate the distance of first minimum from central maxima
Using formula for distance
Put the value into the formula
(b). We need to calculate the spacing between maxima in sound intensity
Using formula for the distance of first maxima
Hence, The distance of first minimum from central maxima is 4.25 m
The spacing between maxima in sound intensity is 8.5 m.