A dust particle with mass of 5.4×10−2 g and a charge of 2.3×10−6 C is in a region of space where the potential is given by V(x)=
1 answer:
Answer:
1.6 m/s^2
Explanation:
Hello!
To calculate the acceleration we must know the electric field. The electric field and the potential are related by:
If the particle starts at 2.3m, the electric field is:
E = 36.869 V/m = 36.869 N/C
So, the force on the particle is:
F = q E = 2.3×10^−6 C * 36.869 N/C = 8.48 x 10^-5 N
And its acceleration is :
a = F/m = 8.48 x 10^-5 N / 5.4×10−5 kg = 1.57 m/s^2
Rounded to two significant figures:
1.6 m/s^2
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Answer:
T=1.566 N.m
Explanation:
Given that:
rotational speed of the scrank shaft, N = 2500 rpm
power produced by one cylinder, P = 410 W
We know, in case of rotational power:
where: T= torque
Substituting the respective values in the above eq.
T=1.566 N.m is the torque applied by the each piston of the engine.
Answer:
The final temperature of both objects is 400 K
Explanation:
The quantity of heat transferred per unit mass is given by;
Q = cΔT
where;
c is the specific heat capacity
ΔT is the change in temperature
The heat transferred by the object A per unit mass is given by;
Q(A) = caΔT
where;
ca is the specific heat capacity of object A
The heat transferred by the object B per unit mass is given by;
Q(B) = cbΔT
where;
cb is the specific heat capacity of object B
The heat lost by object B is equal to heat gained by object A
Q(A) = -Q(B)
But heat capacity of object B is twice that of object A
The final temperature of the two objects is given by
But heat capacity of object B is twice that of object A
Therefore, the final temperature of both objects is 400 K.