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lina2011 [118]
4 years ago
10

The circle below is centered at the point (2,-1) and has a radius of length 3. What is iis equation?

Mathematics
2 answers:
Aleksandr [31]4 years ago
5 0

\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{2}{ h},\stackrel{-1}{ k})\qquad \qquad radius=\stackrel{3}{ r}\\[2em] [x-2]^2+[y-(-1)]^2=3^2\implies (x-2)^2+(y+1)^2=9

Elena L [17]4 years ago
3 0

Answer: (x-2)^2+(y+1)^2=9

Step-by-step explanation:

The equation of a circle having center (h,k) and radius r is given by :-

(x-h)^2+(y-k)^2=r^2

Given: Vertex of circle= (2,-1)

Radius of circle= 3 units

Then the equation of a circle will be :

(x-2)^2+(y-(-1))^2=3^2\\\\\Rightarrow\ (x-2)^2+(y+1)^2=9

Hence, the equation of circle = (x-2)^2+(y+1)^2=9

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Given f (x) = x2 + 5x + 6, what is f of the quantity 2 plus h end quantity minus f of 2 all over h equal to?
scoray [572]

We want to get the difference quotient for the given function, we will get see that the difference quotient is equal to:

f'(x) = 2x + 5

<h3>The difference quotient:</h3>

For a given function f(x), we define the difference quotient as:

\lim_{h \to 0}  \frac{f(x + h) - f(x)}{h}

In this case, we have:

f(x) = x^2 + 5x + 6

Replacing that in the difference quotient we get:

\lim_{h \to 0}  \frac{(x + h)^2 + 5*(x + h) + 6 - x^2 - 5x - 6}{h}\\\\\lim_{h \to 0}  \frac{x^2 + 2xh + h^2 + 5*x + 5*h + 6 - x^2 - 5x - 6}{h}\\\\\lim_{h \to 0}  \frac{ 2xh + h^2 + 5*h }{h}\\

Now we can cancel the factor h to get:

\lim_{h \to 0}  2x + h + 5 = 2x + 0 + 5 = 2x + 5

So the difference quotient is equal to 2x + 5.

If you want to learn more about difference quotients, you can read:

brainly.com/question/4224465

5 0
3 years ago
Which is a rational number between -12 and -11.25?
cupoosta [38]
Well a and b both would be.
5 0
3 years ago
Read 2 more answers
3y – 28 &gt; -9 solve the inequality
Vadim26 [7]

Answer:

y>\frac{19}{3}

Step-by-step explanation:

3y-28>-9\\\\3y-28+28>-9+28\\\\3y>19\\\\\frac{3y>19}{3}\\\\ \boxed{y>\frac{19}{3}}

Hope this helps.

4 0
3 years ago
An amusement park has 11 roller coasters. In how many ways can you choose 4 of the roller coasters to ride during your visit to
Vadim26 [7]
4!=4*3*2*1=24
11!=11*10*9*8*7*6*5*4*3*2*1=39916800
7!=7*6*5*4*3*2*1=5040
n choose k
how many ways are there to choose k rollercoasters from n choices?

\left(\begin{array}{ccc}n\\k\end{array}\right)=\frac{n!}{k!(n-k)!}

\left(\begin{array}{ccc}11\\4\end{array}\right)=\frac{11!}{4!(11-4)!}=\frac{39916800}{24(7)!}=\frac{39916800}{24(5040)}=\frac{39916800}{120960}=330



330 ways






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4 years ago
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Answer:

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7 0
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