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2 years ago

True or false: 4[6 2(6 4)]<20

Mathematics

1 answer:

Nuetrik [128]2 years ago

7 0

The answer is true i believe

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If 1 egg boiled 3 minutes then6 eggs r boiled in..................min

AleksAgata [21]

count by 3,

3 6 9 12 15 18

18 minutes for 6 eggs.

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3 years ago

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HELP PLEASE!!!!!!!!!!!!!!!!!!!!!

AlexFokin [52]

Answer:

Step-by-step explanation:

Let x represent the number of cars that Jamie washes.

Let y represent the number of pies that Stella makes.

The amount of money needed by Jamie and Stella to sign up for the trip is $600 each

Jamie earns $25 for each car washed. This means that if he washes x cars, he would earn 25×x =$25x

Stella earns $15 for each pie made.

This means that if she makes y pies, she would earn 15×y =$15y

Part 1) The inequality is

25x greater than or equal to 600

Part 2)The inequality is

15y greater than or equal to 600

Part 3) Stella only has enough supplies to make 40 pies. Total amount made from 40 pies would be 40×15 = 600

Jamie's earnings is

25x greater than or equal to 600

Stella's earnings is

15y lesser than or equal to 600

Part 4) Maximum amount of money that Stella can earn is 15×40 = $600

Therefore, Stella can afford to sign up for the trip.

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3 years ago

The same amount of principal is invested in different accounts earning the same interest rate. Which of the following accounts w

denis23 [38]

D. Because the interest is compounded more frequently, you will get more money. This is because it allows you to earn interest on previous interest more frequently.

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3 years ago

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Solve for x:

Pepsi [2]

D x=5 jhhhhhhgfrcrcrvtvrvtvrvgniby

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2 years ago

How do I solve this algebra two btw

pychu [463]

$\bf \begin{cases} x^2+y^2=400\\ \boxed{y}=x-28 \end{cases}\qquad \stackrel{\textit{substituting on the 1st equation}}{x^2+\left( \boxed{x-28} \right)^2=400} \\\\\\ x^2+(x^2-56x+28^2)=400\implies x^2+x^2-56x+28^2=400 \\\\\\ 2x^2-56x+784=400\implies 2x^2-56x+384=0 \\\\\\ 2(x^2-28x+192)=0\implies x^2-28x+192=0 \\\\\\ (x-16)(x-12)=0\implies x = \begin{cases} 16\\ 12 \end{cases}$

now that we know what are the x-values, what are the y-values? well, we can just use the 2nd equation, since we know that y = x - 28, then

$\bf y = x - 28\implies \stackrel{\textit{when x = 16}}{y = 16 - 28}\implies y = -12 \\\\\\ y = x - 28\implies \stackrel{\textit{when x = 12}}{y = 12 - 28}\implies y = -16 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill (\stackrel{x}{16}~~,~~\stackrel{y}{-12})\qquad,\qquad (\stackrel{x}{12}~~,~~\stackrel{y}{-16})~\hfill$

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2 years ago