Question

A parallel circuit is constructed with three different branches. An ammeter is placed in each of the branches to measure the branch currents. An ammeter is also placed outside the circuit to measure the current in the voltage source.
If I1 = 2.8 A, I2 = 4.1 A, and I3 = 4.8 A, then what is the current in the battery (I_battery)?

Answer 1

Answer:

Current in the battery will be 11.7 A

Explanation:

We have given that the there is parallel circuit with three different branches.

Current in each branch is $I_1=2.8A$, $I_2=4.1A$,$I_2=4.8A$

We have to find the current I in the battery

It is known that in parallel circuit current is sum of current in each branches

So current in the battery will be equal to

$I=I_1+I_2+I_3$

$I=2.8+4.1+4.8=11.7A$

Therefore current in the battery will be 11.7 A