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OleMash [197]
3 years ago
7

A diffraction grating with 1000 lines per mm is used in a spectrometer to measure the wavelengths of light emitted from a gas di

scharge tube. You measure the diffraction angle to be at 20° for one emission line. What would happen to this emission line’s diffraction angle if you replaced the diffraction grating with one having 500 lines per mm instead
Physics
1 answer:
frez [133]3 years ago
4 0

Answer:

= 9.8°

Explanation:

Width of one slit (a₁ ) = 1 / 1000 mm=0.001 mm = 10⁻⁶ m.

width of one slit in case 2 (a₂ ) = 1/500 =2 x 10⁻⁶ m

angular position of fringe, Sinθ  = n λ /a

n is order of fringe , λ is wave length of light and a  is slit aperture

So Sinθ  ∝ 1 / a

Sin θ₁ /Sin θ₂ = a₂/a₁ ;

Sin20°/sinθ₂ = 2 / 1

sinθ₂ = Sin 20° / 2 = .342/2 = .171

θ₂ = 9.8 °

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Answer:

The correct answer is;

Change of phase.

Explanation:

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The state of a substance will change, depending on the surrounding temperature and the applied pressure and the energy required for the substance to change its state is known as latent heat.

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3 years ago
Suppose the force of gravity on the electron was comparable to the electric force created by the deflection plates. how would th
Alexandra [31]
"F=Vector Sum Of The Two Forces" Is the answer.
3 0
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Why should it take significantly more energy to move a beam of alpha particles than a beam of beta minus (β–) particles?
a_sh-v [17]
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4 0
3 years ago
Read 2 more answers
If an automobile engine delivers a power of 50.0 hp, how much time will it take for the engine to do 6.40 x 10^4 j of work? (1 h
aleksandrvk [35]

Given data

Power (P) = 50 hp,

                = 50 × 746,  we know that 1 hp = 746 W.

                = 37300 Watts      (Watt = J/s)  

Work  = 6.40 ×10⁴ J

Power is defined as rate of doing work and the unit of power is<em> Watt.</em>

Mathematically,

         Power = (Work / time)   Watts

                     = 6.40 ×10⁴ / time

          37300 W = 6.40 ×10⁴ J /time      (Where time in seconds)

         => time = Work/Power

                      = 6.40 ×10⁴/37300

                      = <em>1.74 seconds  </em>

<em>  </em><em>Therefore , the engine need 1.74 seconds to do 6.40 6.40 ×10⁴ J of work </em>

<em> </em>


7 0
3 years ago
I need help
musickatia [10]

Answer:

C

Explanation:

4 0
3 years ago
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