Answer:
Explanation:
For the cat to stay in place on the merry go round without sliding the magnitude of maximum static friction must be equal to magnitude of centripetal force
Where the r is the radius of merry-go-round and v is the tangential speed
but
So we have
Substitute the given values
So
Answer:
Gravitational field strength =weight/mass
Explanation:
14.8N/4.0kg
3.7N/kg
We have that the cricket’s displacement is
From the Question we are told that
Start position 5 meter mark
It jumps to the 10 meter mark.
it jumps back to the 6 meter mark.
Generally the equation for cricket’s displacement. is mathematically given as
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Like charges repel and opposite charges attract.
