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Sati [7]
3 years ago
5

A test charge of -1.4 × 10-7 coulombs experiences a force of 5.4 × 10-1 newtons. Calculate the magnitude of the electric field c

reated by the negative test charge.
A. 1.4 × 106 newtons/coulomb
B. 1.9 × 106 newtons/coulomb
C. 5.4 × 10-1 newtons/coulomb
D. 3.6 × 106 newtons/coulomb
Physics
2 answers:
kotykmax [81]3 years ago
8 0

Answer: D. 3.6*10^-6

Explanation:

Electric field strength E= Force on a charge / charge

E = F/q

E = 5.4*10^-1 / 1.4*10^-7

E = 3.857*10^6 N/C

mr_godi [17]3 years ago
3 0
I would say C 5.4 x 10-1 Newtons/coulomb
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Answer:

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Explanation:

<u>Given the following data;</u>

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To find the heat energy required;

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Answer:

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        p_1 =  [\frac{1}{2}  \rho v_2^2 + h_2 \rho g +p_2] -[\frac{1}{2} \rho * v_1^2 + h_1 \rho g ]

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Answer:

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