Answer:
D). Y'=
and y'= ![5x^{3}-2x](https://tex.z-dn.net/?f=5x%5E%7B3%7D-2x)
Step-by-step explanation:
We are given the equation
.
On simplifying this equation, we get ![4x^{5}-12x^{4}-5x^{3}+8x=0](https://tex.z-dn.net/?f=4x%5E%7B5%7D-12x%5E%7B4%7D-5x%5E%7B3%7D%2B8x%3D0)
i.e. Let, Y'=
and y'= ![5x^{3}-2x](https://tex.z-dn.net/?f=5x%5E%7B3%7D-2x)
Now, according to the options,
A) Y =
= -Y' , that means the graph will be inverse of the required graph.
B) As the coefficient of 'x' in our given equation and the equation of option B are different, both will have different graphs.
C) As y =
= -y', this means that the graph will be inverse of the required graph.
Hence, all above options are discarded and so option D is correct.