If the CAT operates with a constant speed of 53 mph (which means it beats 53 miles in one hour) and makes a trip in about 2 and 1/2 hours, we just have to multiply 53 by 2 1/2 to find out the overall distance it's beating in that time:
53 * 2 1/2 =
= 53 * 2.5 =
= 132.5
Answer: City A is about <u>132.5 miles</u> from city B.
By setting up a system of equations we can easily solve this problem. Let's denote Jane's working hours with x and Jack's working hours with y. Since they don't want to work more than 65 hours, the first equation is x+y=65. The second equation is 14x+7y=770. By solving this system of equation

, we find that y=20 hours, which is Jack's maximum working hours.
Answer:
trapezoid area = ((sum of the bases) ÷ 2) • height
trapezoid area = ((6 + 12) / 2) * height
trapezoid area = 18 / 2 * height
height = 99/9 = 11
Step-by-step explanation:
I think is yes but I’m not sure