Question

A local park is building a sand volleyball court 40 feet long and 15 feet wide. They are paying $3000 to have the sand put into the court. How much does the court cost per square foot of sand?

Answer 1

Answer:

The court cost $5 per square foot of sand

Step-by-step explanation:

step 1

Find the area of the volleyball court

The area of the rectangular court is equal to

$A=LW$

we have

$L=40\ ft$

$W=15\ ft$

substitute

$A=(40)(15)=600\ ft^{2}$

step 2

Divide the total cost to have the sand put into the court by the area of the court

so

$\frac{3,000}{600}\frac{\ }{ft^{2}}=5\frac{\ }{ft^{2}}$

therefore

The court cost $5 per square foot of sand

Answer 2

Answer:

$5 per square feet.

Step-by-step explanation:

A local park is building a stand volleyball court that is 40 feet long and 15 feet wide.

Area of the volleyball court = length × width

                                              = 40 × 15

                                              = 600 feet²

They are paying $3,000 to have the stand put into the court.

The cost per square foot of stand =  $\frac{3000}{600}$

                                                        = 5 dollar per square

The cost is $5 per square feet of stand.