4 years ago

What goes in the space? (3x − ...)2 = 9x2−6x+1 I will give points and brainliest!

Mathematics

1 answer:

Crazy boy [7]4 years ago

6 0

${(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2}$

$(3x - ...)^{2} = 9 {x}^{2} - 6x + 1 \\ {(3x - 1)}^{2} = 9 {x}^{2} -6x + 1$

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RSB [31]

Answer: (8,5)

Step-by-step explanation:

1. You have that each point of a function has coordinates (x,y), then, you can substitute the value of x of each point shown in the options to obtain the y.

2. You can rewrite the function as following:

$y=8-\sqrt[3]{x}$

Then:

$x=-64$

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(-64,12) lies on the graph

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(125,3) lies on the graph

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(343,1) lies on the graph

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4 years ago

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Answer:

Step-by-step explanation:

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