3 years ago

Is it a function? If you said no, which x value repeats, making it not a function ?

Mathematics

1 answer:

nata0808 [166]3 years ago

7 0

Answer:

yes

Step-by-step explanation:

there are no x values that are repeating

You might be interested in

What is the answer for 144=-12(x+5) must show work

miskamm [114]

Answer:

Step-by-step explanation:

$-12(x+5)=144\qquad\text{divide both sides by (-12)}\\\\\dfrac{-12(x+5)}{-12}=\dfrac{144}{-12}\\\\x+5=-12\qquad\text{subtract 5 from both sides}\\\\x+5-5=-12-5\\\\x=-17$

8 0

3 years ago

Read 2 more answers

Help with this, giving 20 points!

Bond [772]

Answer:

Step-by-step explanation:

the shape is a rhombus the are is 24

3 0

3 years ago

Ms. Armstrong is a carpenter. She keeps her tools in a cube-shaped box in her truck. Ms. Armstrong's toolbox is 15 inches long o

Debora [2.8K]

to find the volume you would multiply length width and height

4 0

3 years ago

Read 2 more answers

Elvera Hilton earns $12 an hour at her job. The hours she worked during each of the last four weeks are shown below

Minchanka [31]

Answer:

12x7 4 times add it up u got the anwser

6 0

2 years ago

write a linear equation that intersects y=x^2 at two points. Then write a second linear equation that intersects y=x^2 at just o

Liula [17]

We know that $y = x^2$ is a parabola, concave up, with vertex in the origin $(0,0)$

So, we may use three horizontal lines for our purpose: any horizontal line above the x axis will intersect the parabola twice. The x axis itself intersects the parabola once on the vertex, while any horizontal line below the x axis won't intercept the parabola.

Here's the examples:

The horizontal line $y = 4$ intercepts the parabola twice: the system $y = x^2,\ y = 4$ is solved by $x^2=4 \implies x = \pm 2$
The horizontal line $y=0$ intercepts the parabola only once: the system is $y=x^2,\ y=0$ which yields $x^2=0\implies x=0$ which is a repeated solution
The horizontal line $y=-5$ intercepts the parabola only once: the system is $y=x^2,\ y=-5$ which yields $x^2=-5$ which is impossible, because a squared number can't be negative.

5 0

3 years ago