Answer:
u should give me the formula for ur question cuz I kind of understand but I did it years ago
Answer:
10/13 ≈ 76.9%
Step-by-step explanation:
P(A∪B) = P(A) +P(B) -P(A∩B)
P(plays basketball ∪ plays baseball)
= P(plays basketball) +P(plays baseball) -P(plays both)
P(plays basketball ∪ plays baseball) = 16/26 +9/26 -5/26 = 20/26 = 10/13
P(plays basketball or baseball) = 10/13 ≈ 76.9%
he elements of the Klein <span>44</span>-group sitting inside <span><span>A4</span><span>A4</span></span> are precisely the identity, and all elements of <span><span>A4</span><span>A4</span></span>of the form <span><span>(ij)(kℓ)</span><span>(ij)(kℓ)</span></span> (the product of two disjoint transpositions).
Since conjugation in <span><span>Sn</span><span>Sn</span></span> (and therefore in <span><span>An</span><span>An</span></span>) does not change the cycle structure, it follows that this subgroup is a union of conjugacy classes, and therefore is normal.
300+5+20 COULD BE ONE WAY
