Answer:
(221.39, 300.61) and (255.2223, 266.7777)
Step-by-step explanation:
Given that X, the lengths of pregnancies in a small rural village are normally distributed with a mean of 261 days and a standard deviation of 17 days
Middle 98% would lie on either side of the mean with probability ±2.33 in the std normal distribution on either side of 0
Corresponding we have x scores as
Between 
and 
i.e. in the interval = (221.39, 300.61)
If sample size = 47, then std error of sample would be
So 98% of pregnancies would lie between
and 
= (255.2223, 266.7777)
Y2 - y1/x2 - x1 = slope
4 - 8/ 9 - 5 = slope
-4/4 = slope
-1 = slope
hope this helps :)
Step 1. Substitute y for f(x)
Step 2. Switch x and y.
Step 3. Solve for y.
Step 4. Substitute f(x) for y.
Answer:
hope it's help you ok have a good day
Answer:
61.69?
Step-by-step explanation:
Are you asking what 31% of 119 is? If so, then the answer would be 61.69.
Because (119)0.31=61.69
(To make a percent, you take a decimal out of 1, and multiply. 0.31 would be 31, because we would multiply it by 100, becuase you can only get to 100%. Then you woukd do the opposite, reverse it by dividing by 100. Which then, you would get 0.31)
Hope that helped.
