the area of a mirror is 225 and its width is 13 3/4 would it fit in a space thats 15 inches by 16 inches

Mathematics

1 answer:

Delvig [45]3 years ago

5 0

No duhh, sorry, yes, dont trust because i did not do any math here XD

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A triangle has one leg measuring 10 inches and the hypotenuse measuring 20 inches. the other leg measures 10\sqrt[]{3} 10 3 inch

stiv31 [10]

From the description given for the triangle above, I think the type of triangle that is represented would be a right triangle. This type of triangle contains a right angle and two acute angles. In order to say or prove that it is a right triangle, it should be able to satisfy the Pythagorean Theorem which relates the sides of the triangle. It is expressed as follows:

c^2 = a^2 + b^2

where c is the hypotenuse or the longest side and a, b are the two shorter sides.

To prove that the triangle is indeed a right triangle, we use the equation above.

c^2 = a^2 + b^2
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mrs_skeptik [129]

We know that

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so

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DanielleElmas [232]

We can change the law of sines a little bit to match our problem.

$\sf\dfrac{sin(X)}{x}=\dfrac{sin(Y)}{y}=\dfrac{sin(Z)}{z}$

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Plug in what we know:

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Multiply 'z' to both sides:

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Minimum: 2
Maximum: 30
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faltersainse [42]

Answer:

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