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2 years ago

Question 4

Mathematics

1 answer:

ololo11 [35]2 years ago

5 0

Answer:

4570

Step-by-step explanation:

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In a certain Algebra 2 class of 30 students, 19 of them play basketball and 12 of them play baseball. There are 8 students who p

Alenkinab [10]

Answer:

Probability that a student chosen randomly from the class plays basketball or baseball is $\frac{23}{30}$ or 0.76

Step-by-step explanation:

Given:

Total number of students in the class = 30

Number of students who plays basket ball = 19

Number of students who plays base ball = 12

Number of students who plays base both the games = 8

To find:

Probability that a student chosen randomly from the class plays basketball or baseball=?

Solution:

$P(A \cup B)=P(A)+P(B)-P(A \cap B)$ ---------------(1)

where

P(A) = Probability of choosing a student playing basket ball

P(B) = Probability of choosing a student playing base ball

P(A \cap B) = Probability of choosing a student playing both the games

Finding P(A)

P(A) = $\frac{\text { Number of students playing basket ball }}{\text{Total number of students}}$

P(A) = $\frac{19}{30}$ --------------------------(2)

Finding P(B)

P(B) = $\frac{\text { Number of students playing baseball }}{\text{Total number of students}}$

P(B) = $\frac{12}{30}$ ---------------------------(3)

Finding $P(A \cap B)$

P(A) = $\frac{\text { Number of students playing both games }}{\text{Total number of students}}$

P(A) = $\frac{8}{30}$ -----------------------------(4)

Now substituting (2), (3) , (4) in (1), we get

$P(A \cup B)= \frac{19}{30} + \frac{12}{30} -\frac{8}{30}$

$P(A \cup B)= \frac{31}{30} -\frac{8}{30}$

$P(A \cup B)= \frac{23}{30}$

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3 years ago

In 2006,the General Social Survey (which is conducted uses a method similar to simple random sampling) included a question that

mars1129 [50]

Answer:

Assumptions are not met. Can not make confidence interval.

Step-by-step explanation:

In the General Social Survey, sample size is 1514.

The proportion of those who see themselves social is $\frac{470}{1514}$ ≈ 0.31

To give an 95% confidence interval, we should be able to calculate margin of error of the sample mean, which is given by the formula

M± $z*\frac{s}{\sqrt{N} }$ where M is the mean of the sample (in the General Social Survey it is 0.31), z is z-score for the 95% confidence level(approx. 1.94), s is the standard deviation of the sample, N is the size of the sample(in this example it is 1514).

Since we don't know the standard deviation of the sample, we cannot give a confidence interval.

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3 years ago