A circle has a radius of 10 inches. Find the approximate length of the arc intersected by a central angle of 2(pi)/3

1 answer:

6 0

$\bf \textit{arc's length}\\\\ s=r\theta ~~ \begin{cases} r=&radius\\ \theta =&angle~in\\ &radians\\ \cline{1-2} r=&10\\ \theta =&\frac{2\pi }{3} \end{cases}\implies s=10\left( \cfrac{2\pi }{3} \right)\implies s=\cfrac{20\pi }{3}\implies s\approx 20.94$

You might be interested in

if k is a half-plane determined by QR, then for every real number 0 < x < or = to 180, there is exactly one ray, QQP, that

zloy xaker [14]

Let me start from the meaning of half plane.you must have learned that there are two axes X and Y axes which includes positive X axes and negative X axes and there is positive Y axes and negative y axes. So there are four quadrants which i have explained in the figure. I have explained the meaning of Half plane in the Diagram also. Half plane=Figure obtained by covering any two adjacent regions of the coordinate axes.So we get four half planes.

Now your question is k is a half plane determined by QR, such that 0<x≤180 and there is exactly one ray QRP that lies in k

So, $0< \angle PQR \leq 180^\cir{0}$