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rewona [7]
3 years ago
12

(5,0) and (8,4) positive or negative

Mathematics
2 answers:
aivan3 [116]3 years ago
5 0

<span>Positive integers are all the whole numbers greater than zero: 1, 2, 3, 4, 5, ... . Negative integers are all the opposites of these whole numbers: -1, -2, -3, -4, -5, </span>

<span>So they are positive</span>

goldfiish [28.3K]3 years ago
4 0
I think its positive.. lemme know if its wrong

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Answer:

48.25

Step-by-step explanation:

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If it takes Mr. Williams 1/5 hour to grade each of his students’ tests, how many tests can he grade in 4 hours?
MaRussiya [10]

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Find the slope and the y-intercept of the line y=1/2x
irina [24]
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4 years ago
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Arada [10]

Answer: $245.01

Step-by-step explanation:

A=P(1+rn)n⋅t

A = total amount

P = principal or amount of money deposited,

r = annual interest rate

n = number of times compounded per year

t = time in years

In this example we have

P=$200 , r=7% , n=1 and t=3 years

After plugging the given information we have

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Hope this helps, give me brainliest

4 0
3 years ago
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The function f(x)f(x) is a quartic function and the zeros of f(x)f(x) are -6−6, -5−5, -2−2 and 11. Assume the leading coefficien
Luden [163]
<h2>Answer: </h2>

\boxed{f(x) = 11x^4 + 22x^3 - 1001x^2 - 5632x - 7260}

<h2>Explanation: </h2>

A quartic function is a function given by the the following equation in standard form:

f(x)=a_{4}x^4+a_{3}x^3+a_{2}x^2+a_{1}x+a_{0} \\ \\ \\ Where: \\ \\ a_{4},a_{3},a_{2},a_{1},a_{0} \ \text{are constant} \\ \\ \text{and} \ a_{4} \ \text{is the leading coefficient}

From the statement we must assume the leading coefficient of f(x) is 11, so:

a_{4}=11

The zeros are:

x=-6 \\ \\ x=-5 \\ \\ x=-2 \\ \\ x=11

So, we can write:

f(x)=11(x-(-6))(x-(-5))(x-(-2))(x-11) \\ \\ \\ So: \\ \\ \mathrm{Rule}:-\left(-a\right)=a \\ \\ \\ Then: \\ \\ f(x)=11\left(x+6\right)\left(x+5\right)\left(x+2\right)\left(x-11\right)

Expand:\left(x+6\right)\left(x+5\right):\ x^2+11x+30: \ \text{Distributive Property} \\ \\ \\ Then: \\ \\ f(x)=11\left(x^2+11x+30\right)\left(x+2\right)\left(x-11\right) \\ \\ \\ Expand:\left(x^2+11x+30\right)\left(x+2\right):\ x^3+13x^2+52x+60:  \ \text{Distributive Property} \\ \\ \\ Then: \\ \\ f(x)=11\left(x^3+13x^2+52x+60\right)\left(x-11\right)

Expand: \left(x^3+13x^2+52x+60\right)\left(x-11\right):\ x^4+2x^3-91x^2-512x-660 \\  (Distributive \ property)

Finally:

f(x) = 11(x^4 + 2x^3 - 91x^2 - 512x - 660) \\ \\ \boxed{f(x) = 11x^4 + 22x^3 - 1001x^2 - 5632x - 7260}

3 0
3 years ago
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