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zhenek [66]
4 years ago
11

A new building that costs $1,000,000 has a useful life of 10 years and a scrap value of $200,000. Using straight-line depreciati

on, find the equation for the value V in terms of t, where t is in years. (Make sure you use t and not x in your answer.)
Mathematics
1 answer:
vazorg [7]4 years ago
8 0

Answer:

V = -80,000*t + 1,000,000

Step-by-step explanation:

Given:

- The original cost V_i = $1,000,000

- Scrap Value V_f = $200,000

- Total number of years n = 10

Find:

Using straight-line depreciation, find the equation for the value V in terms of t, where t is in years.

Solution:

- The straight line depreciation method means their is a linear relationship between the value of building and time elapsed till useful life. The linear relationship takes a form:

                                 V = m*t + C

Where,

V: It is the current value of the building

m: The rate at which value increase or decrease with time t

C: The initial value of the building

- We will compute constants m and C as follows:

                               m = (V_f - V_i) / ( 10 - 0 )

                               m = (200,000 - 1,000,000) / 10

                               m = - $80,000/year

                               C = V_i = $1,000,000

- Plug the values of the constants evaluated above in the linear expression:

                                V = -80,000*t + 1,000,000

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Answer:

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Step-by-step explanation:

As given

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3 0
3 years ago
Calculate the expected value of playing a lottery ticket game where each ticket costs $5, and the chance of having winning ticke
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Answer:

$4895

Step-by-step explanation:

P(winning) = 1 / 1000000 = 0.000001

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Winning amount = 4,900,000,000 - 5 = 4899999995

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__ X: - 5 _________ 4899999995

P(X) : 0.999999 ___ 0.000001

Expected value E(x) = Σx * p(x)

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E(x) = 4895

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6 0
3 years ago
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Bingel [31]

Answer:

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AB,\ AC,\ AD,\ AE,\\BC,\ BD,\ BE\\CD,\ CE\\DE

Step-by-step explanation:

The sample space of an experiment is a set of all the possible values that satisfies that experiment.

The five supervisors are A, B, C, D and E.

Two are to selected.

The number of ways to select 2 supervisors  from 5 is: {5\choose 2}=\frac{5!}{2!(5-2)!} =\frac{5!}{2!\times 3!}  = 10

The sample space will consist of 10 combinations.

The sample space is:

AB,\ AC,\ AD,\ AE,\\BC,\ BD,\ BE\\CD,\ CE\\DE

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Answer:

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V= l*w*h

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Hope this Helps! :)

Have a nice day! :)

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