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3 years ago

This i questions hellllllllppppppppppppppppppppppppppp

Mathematics

1 answer:

tatuchka [14]3 years ago

8 0

Answer:

I dont understand what you mean by this I questions, but that is the Order of Operations. You use "PEMDAS" to memorize all 4 Order of Operations..

Step-by-step explanation:

You might be interested in

When Liz woke up in the morning, it was 6°F. By the late afternoon, the temperature had dropped 9°F.

Reil [10]

Answer:

-3°F

Step-by-step explanation:

6 - 9 = -3°F

4 0

3 years ago

Bryce has 220 feet of fencing that will enclosure a rectangular corral. One side of the corral will be 48 feet long. What will b

Gala2k [10]

Answer:

10560 square feet

Step-by-step explanation:

If 2 sides are 48 feet, then we are left with

$220-2*48=124$ feet for the remaining side pieces.

$\frac{124}{2} =62$ feet.

So our dimensions must be 48 x 62.

This gives us an area of

$220*48=10560ft^{2}$

6 0

3 years ago

A rectangle is 4xcm wide and 2cm long what do you notice

deff fn [24]

The width of the rectangle is twice the length of the rectangle

<h3>How to compare the dimensions of the rectangle?</h3>

The given parameters are:

Width = 4 cm

Length = 2 cm

Express 4 cm as 2 * 2 cm

Width = 2 * 2 cm

Substitute Length = 2 cm in Width = 2 * 2 cm

Width = 2 * Length

This means that the width of the rectangle is twice the length of the rectangle

Hence, the true statement is that the width of the rectangle is twice the length of the rectangle

Read more about rectangles at:

brainly.com/question/25292087

#SPJ1

4 0

1 year ago

Help me on this please

zalisa [80]

Answer:

1. (x, y) → (x + 3, y - 2)

Vertices of the image

a) (-2, - 3)

b) (-2, 3)

c) (2, 2)

2. (x, y) → (x - 3, y + 5)

Vertices of the image

a) (-3, 2)

b) (0, 2)

c) (0, 4)

d) (2, 4)

3. (x, y) → (x + 4, y)

Vertices of the image

a) (-1, -2)

b) (1, -2)

c) (3, -2)

4. (x, y) → (x + 6, y + 1)

Vertices of the image

a) (1, -1)

b) (1, -2)

c) (2, -2)

d) (2, -4)

e) (3, -1)

f) (3, -3)

g) (4, -3)

h) (1, -4)

5. (x, y) → (x, y - 4)

Vertices of the image

a) (0, -2)

b) (0, -3)

c) (2, -2)

d) (2, -4)

6. (x, y) → (x - 1, y + 4)

Vertices of the image

a) (-5, 3)

b) (-5, -1)

c) (-3, 0)

d) (-3, -1)

Explanation:

To identify each IMAGE you should perform the following steps:

List the vertex points of the preimage (the original figure) as ordered pairs.

Apply the transformation rule to every point of the preimage

List the image of each vertex after applying each transformation, also as ordered pairs.

1. (x, y) → (x + 3, y - 2)

The rule means that every point of the preimage is translated three units to the right and 2 units down.

Vertices of the preimage Vertices of the image

a) (-5,2) (-5 + 3, -1 - 2) = (-2, - 3)

b) (-5, 5) (-5 + 3, 5 - 2) = (-2, 3)

c) (-1, 4) (-1 + 3, 4 - 2) = (2, 2)

2. (x,y) → (x - 3, y + 5)

The rule means that every point of the preimage is translated three units to the left and five units down.

Vertices of the preimage Vertices of the image

a) (0, -3) (0 - 3, -3 + 5) = (-3, 2)

b) (3, -3) (3 - 3, -3 + 5) = (0, 2)

c) (3, -1) (3 - 3, -1 + 5) = (0, 4)

d) (5, -1) (5 - 3, -1 + 5) = (2, 4)

3. (x, y) → (x + 4, y)

The rule represents a translation 4 units to the right.

Vertices of the preimage Vertices of the image

a) (-5, -2) (-5 + 4, -2) = (-1, -2)

b) (-3, -5) (-3 + 4, -2) = (1, -2)

c) (-1, -2) (-1 + 4, -2) = (3, -2)

4. (x, y) → (x + 6, y + 1)

Vertices of the preimage Vertices of the image

a) (-5, -2) (-5 + 6, -2 + 1) = (1, -1)

b) (-5, -3) (-5 + 6, -3 + 1) = (1, -2)

c) (-4, -3) (-4 + 6, -3 + 1) = (2, -2)

d) (-4, -5) (-4 + 6, -5 + 1) = (2, -4)

e) (-3, -2) (-3 + 6, -2 + 1) = (3, -1)

f) (-3, -4) (-3 + 6, -4 + 1) = (3, -3)

g) (-2, -4) (-2 + 6, -4 + 1) = (4, -3)

h) (-2, -5) (-2 + 3, -5 + 1) = (1, -4)

5. (x, y) → (x, y - 4)

This is a translation four units down

Vertices of the preimage Vertices of the image

a) (0, 2) (0, 2 - 4) = (0, -2)

b) (0,1) (0, 1 - 4) = (0, -3)

c) (2, 2) (2, 2 - 4) = (2, -2)

d) (2,0) (2, 0 - 4) = (2, -4)

6. (x, y) → (x - 1, y + 4)

This is a translation one unit to the left and four units up.

Vertices of the pre-image Vertices of the image

a) (-4, -1) (-4 - 1, -1 + 4) = (-5, 3)

b) (-4 - 5) (-4 - 1, -5 + 4) = (-5, -1)

c) (-2, -4) (- 2 - 1, -4 + 4) = (-3, 0)

d) (-2, -5) (-2 - 1, -5 + 4) = (-3, -1)

8 0

3 years ago

What does x equal to

Slav-nsk [51]

If that is a rhombus as it says it is, then the diagonals are perpendicular to one another, meaning where they meet, they form right angles. Therefore, angle x is a 90 degree angle.

3 0

3 years ago