Question

At a newsstand, out of 46 customers, 27 bought the Daily News, 18 bought the Tribune, and 6 bought both papers.

Answer 1

Answer:

$\text{Customer that bought only one paper}=33$

$\text{Customer that bought something other than either of the two papers}=7$

Step-by-step explanation:

We have been given that at a newsstand, out of 46 customers, 27 bought the Daily News, 18 bought the Tribune, and 6 bought both papers.

$\text{Customer that bought only Daily news}=27-6$

$\text{Customer that bought only Daily news}=21$

$\text{Customer that bought only Tribune}=18-6$

$\text{Customer that bought only Tribune}=12$

The customer that bought only one paper would be the sum of customers, who bought only Daily news or Tribune.

$\text{Customer that bought only one paper}=21+12$

$\text{Customer that bought only one paper}=33$

Therefore, 33 customers bought only one paper.

$\text{Customer that bought something other than either of the two papers}=46-(27+18-6)$

$\text{Customer that bought something other than either of the two papers}=46-(45-6)$

$\text{Customer that bought something other than either of the two papers}=46-39$

$\text{Customer that bought something other than either of the two papers}=7$

Therefore, 7 customers bought something other than either of the two papers.