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ollegr [7]
3 years ago
11

Answer correctly and i will give you my account or will give u brainliest

Mathematics
2 answers:
Ivahew [28]3 years ago
8 0

Answer:

1200.96m

Step-by-step explanation:

please give me brainliest

marishachu [46]3 years ago
6 0

Answer:

V = 1200.96 m^{3}

Step-by-step explanation:

V = \pi r^{2} \frac{h}{3} \pi x 9.14^{2} x \frac{13.72}{3} = 1200.95996m^{3}

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A credit union pays 5% annual interest, compounded daily, on savings deposits. Find the value after one year of $500 deposited i
8_murik_8 [283]

Step-by-step answer:

Given:

5% annual interest (APR)

compounded daily

Principal = 500

Solution:

Since it is compounded daily, we first calculate the

daily rate =  5% / 365 = 0.05/365

After one year,

future value

= 500 ( 1 + 0.05/365)^365

= 525.634 (to the tenth of a cent)

note: sometimes a year is considered to be rounded to 360 days, or 366 days for a leap year, but there is practically no difference in the results for this problem.

4 0
3 years ago
Plz help I’ll give 60 I REALLY need help
boyakko [2]

Answer:

a for the first one, i pretty sure

4 0
4 years ago
Read 2 more answers
Find the determinant of the following matrix.
sineoko [7]

Answer:

\left[\begin{array}{ccc}2&-3\\1&-4\end{array}\right]=-5

Step-by-step explanation:

Given:

The given matrix is.

\left[\begin{array}{ccc}2&-3\\1&-4\end{array}\right]

the determinant of the above matrix is.

\left[\begin{array}{ccc}2&-3\\1&-4\end{array}\right]=2\times (-4) - (-3)\times 1

\left[\begin{array}{ccc}2&-3\\1&-4\end{array}\right]=-8 - (-3)

\left[\begin{array}{ccc}2&-3\\1&-4\end{array}\right]=-8 +3

\left[\begin{array}{ccc}2&-3\\1&-4\end{array}\right]=-5

Therefore, the determinant of the matrix is -5

6 0
3 years ago
I need some help on this with my geometry stuff
AleksandrR [38]

Length of AA' = √(5^2 + 2^2) = √29 = 5.39

Answer

5.39

7 0
4 years ago
in how many ways can you make change for 20$ using quarters and dimes , with at least one of each coin being used ?
Alenkinab [10]
With dimes it will take 200
4 0
3 years ago
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