Let a = 693, b = 567 and c = 441
Now first we will find HCF of 693 and 567 by using Euclid’s division algorithm as under
693 = 567 x 1 + 126
567 = 126 x 4 + 63
126 = 63 x 2 + 0
Hence, HCF of 693 and 567 is 63
Now we will find HCF of third number i.e., 441 with 63 So by Euclid’s division alogorithm for 441 and 63
441 = 63 x 7+0
=> HCF of 441 and 63 is 63.
Hence, HCF of 441, 567 and 693 is 63.
She has $18.50 so she needs $39.50.
6.50×3= 19.50
18.50+19.50= 38
5.25×4=21
38+21=59
Maya would have enough money to go on the trip.
Answer: $11.48
Step-by-step explanation:
First of all, you have to multiply 3.25 by 2.55 because the grapes are 2.55 per pound. That makes 8.2875 for the first occasion. Next, you have to multiply 1.25 by 2.55 for the second occasion. That makes 3.1875. You then have to add 8.2875 and 3.1875. You get 11.47500, and that rounded to the nearest cent is $11.48.
Tan52° = x/29
The angle of elevation is 52°, so that must be inside the tan function.
Tan is the ratio of the opposite side to the adjacent side. Jessica’s height is unknown, so we can call that x. The adjacent side of the triangle is the shadow, which is 29’m. Since tan is opposite over adjacent (remember SOH CAH TOA), the fraction must be x/29.
1y - 1/x = 1/60 = x*y =60 = x=60/y
3y - 2(60/y) = 6
3y^2-120=6y
3(y^2-40-2y) =0
y^2-40-2y=0
y = 7.4
3(7.4)-2x=6
22.2-2x = 6
2x = -16.2
x = -8.1