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3 years ago

What are four consecutive odd integers that equals 184

Mathematics

1 answer:

Serggg [28]3 years ago

3 0

1st: 2x-3 2nd: 2x-1 3rd: 2x+1 4th: 2x+3

adding the above you get 8x=184

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What is the answer to this math question!?

Nostrana [21]

Answer:

C) 37

Step-by-step explanation:

1/2(PQ)=RQ

2.5x+17=6x-11

17=3.5x-11

28=3.5x

x=8

RQ=6(8)-11

RQ=48-11

RQ=37

5 0

2 years ago

Read 2 more answers

The area of the conference table in Mr. Nathan’s office must be no more than 175 ft2. If the length of the table is 18 ft more t

valentina_108 [34]

The answer is 0 < x ≤ 7

First, we know that width = x
Which means that length = x +18

So, the possible equation for the Table's area is

X (X + 18) ≤ 175

X^2 + 18x - 175 ≤ 0

Next, we need to calculate is by using complete square method
x^2 + 18x + 81 ≤ 175 + 81

(x + 9)^2 ≤ 256

|x + 9| ≤ sqrt(256)

|x + 9| ≤ +-16

-16 ≤ x + 9 ≤ 16

-16 - 9 ≤ x ≤ 16 - 9

-25 ≤ x ≤ 7

Since the width couldn't be negative, we can change -25 with 0,

so it become
 0 < x ≤ 7

7 0

2 years ago

From a height of 50 meters above sea level on a cliff, two ships are sighted due west. The angles of depression are 61° and 28°.

Olenka [21]

Answer:

The ships are 66 meters apart.

Step-by-step explanation:

For the sake of convenience, let us label ships A and B

As shown in the figure, the distances to the ships from right triangles.

The distance to the ship A is $d_1$ and it is given by

$tan (61^o)= \dfrac{50}{d_1}$

$d_1=\dfrac{50}{tan (61^o)}$

$\boxed{d_1= 27.71m}$

And the distance to the ship B is $d_2$ and is given by

$tan (28^o)= \dfrac{50}{d_2}$

$d_2=\dfrac{50}{tan (28^o)}$

$\boxed{ d_2=94.04m}$

Therefore, the distance $d$ between the ships A and B is

$d= d_2-d_1=94.04-27.7\\\\\boxed{d=66m}$

In other words, the ships are 66 meters apart.

8 0

3 years ago

Read 2 more answers

Trigonometry and trigonometric functions

zaharov [31]

Answer:

The trigonometric functions include the following 6 functions: sine, cosine, tangent, cotangent, secant, and cosecant. For each of these functions, there is an inverse trigonometric function. The trigonometric functions can be defined using the unit circle.

Step-by-step explanation:

6 0

2 years ago

A rectangular box has a square base with an edge length of x cm and a height of h cm. The volume of the box is given by V = x2h

creativ13 [48]

It is given in the question that

A rectangular box has a square base with an edge length of x cm and a height of h cm. The volume of the box is given by

$V = x^2h cm^3$

And the edge length of the base is 12 cm, the edge length of the base is decreasing at a rate of 2 cm/min, the height of the box is 6 cm, and the height is increasing at a rate of 1 cm/min.

Here we differentiate V with respect to t, and we use product rule, that is

$V = 2xh(dx/dt)+ x^2(dh/dt)$

Substituting the given values , we will get

$[tex]dV/dt = 2(12)(6)(-2)+ 12^2(1)$ [/tex]

$dV/dt = -288+144 = -144cm^3/min$

So at that moment, the volume is decreasing at the rate of

$144 cm^3/min$

4 0

2 years ago

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