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olga nikolaevna [1]
2 years ago
7

In the first half of a basketball game, a player scored 9 points on free throws and then scored a number of 2-port

Mathematics
1 answer:
Mashcka [7]2 years ago
8 0

Answer: I thin The first one 2r+3r+9

Step-by-step explanation: Because he scored a number of 2 port shots which means he scored more than one but the 9 points is just 9 points from free throws which gives only 1 point each and 3 port shots and much as 2 point shots so 3r also

2r+3r+ just 9

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For this case we have the following expression:

\frac {216 ^ {n-2}} {(\frac {1} {36}) ^ {3n}} = 216

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Rewriting:

(6 ^ 3) ^ {n-3} = (\frac {1} {6 ^ 2}) ^ {3n}\\6 ^ {3n-9} = \frac {1} {6 ^ {6n}}\\6^{ 3n-9} * 6^{ 6n} = 1

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n = 1

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