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Gnoma [55]
3 years ago
14

Two forces with magnitudes of 150 and 75 pounds act on an object at angles of 30° and 150°, respectively. Find the direction and

magnitude of the resultant force. Round to two decimal places in all intermediate steps and in your final answer. (2 points)
Mathematics
1 answer:
yarga [219]3 years ago
6 0

Answer:

The resultant force magnitude is  129.90 pounds at angle of 60°

Step-by-step explanation:

Two given forces and resultant force form right triangle. The first force (150 pounds) is hypotenuse, the second force ( 75 pounds) and resultant force are right sides of the right triangle.

Then we can write pythagorin theorem

R= √150∧2 - 75∧2 = √ 22500-5625 = √16875 = 129.90

Good luck!!!

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sammy [17]

<u>Answer:</u>

D) 6x^2 - 8y^2 = 50

-6x^2 - 2y^2 = 11

<u>Step-by-step explanation:</u>

We are given the following two expressions:

3x^2-4y^2=25

and

-6x^2-2y^2=11

Now if we look at the option D) 6x^2 - 8y^2 = 50&#10; and -6x^2 - 2y^2 = 11, we can observe that the earlier part in the given expression is just a simplification of 6x^2 - 8y^2 = 50.

6x^2 - 8y^2 = 50\\\\2(3x^2-4y^2) = 50\\\\3x^2-4y^2 = \frac{50}{2} \\\\3x^2-4y^2=25

and the later part -6x^2 - 2y^2 = 11 is already the same.

Therefore, the correct answer option is D)  6x^2 - 8y^2 = 50

-6x^2 - 2y^2 = 11.

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3 years ago
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3x-5=1/2x+2x can yall work this out step by step cause I can't
Oxana [17]
Well you can combine like terms. 3x-5=1/4x and that's as far as I got hope this helps. sorry I didn't get all the way through
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In addition to the 1648 highway miles that Laura's family drove to Boston and back, they also took several sightseeing trips alo
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The answer is 5.4 Gallon yeah
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Answer questions 13. And 14. Please! Show minimal work...
ale4655 [162]

13. The equation of the given function is y=4sin[\frac{(t-\frac{4}{3})}{2}]-2

14. The equation of the cotangent function is y=cot[2(t-\frac{1}{3})]+2

Step-by-step explanation:

Let us revise the transformation of the trigonometric function:

y = a f[b(x + c)] + d, where

  • Amplitude is a
  • f represents the trigonometry function
  • Period is 2π/b
  • Phase shift is c (positive is to the left)
  • Vertical shift is d

13.

∵ y = a sin( \frac{2\pi t}{T} ), where a is the amplitude

   and T is the wave in seconds

∵ The amplitude is 4

∴ a = 4

∵ The period is 4π

∴ T = 4π

From the rules above

∵ The period is 2π/b

∴ T = \frac{2\pi }{B}

∴ 4π = \frac{2\pi }{b}

- By using cross multiplication

∴ 4π(b) = 2π

- Divide both sides by 4π

∴ b = \frac{1}{2}

∵ The phase shift is -\frac{4}{3}\pi

∵ c is the phase shift

∴ c = -\frac{4}{3}\pi

∵ The vertical shift is -2

∵ d is the vertical shift

∴ d = -2

Now substitutes the values of a, b, c and d in the form of the equation below

∵ y = a sin[b(t + c)] + d

∴ y=4sin[\frac{1}{2}(t-\frac{4}{3})]-2

You can write it as y=4sin[\frac{(t-\frac{4}{3})}{2}]-2

The equation of the given function is y=4sin[\frac{(t-\frac{4}{3})}{2}]-2

14.

y = cot[b(t + c)] + d

∵ The period = π

∵ The period is 2π/b

- Equate π by 2π/b to find b

∴ π = \frac{2\pi }{b}

- By using cross multiplication

∴ π(b) = 2π

- Divide both sides by π

∴ b = 2

∵ The phase shift is -\frac{1}{3}\pi

∵ c is the phase shift

∴ c = -\frac{1}{3}\pi

∵ The vertical shift is 2

∵ d is the vertical shift

∴ d = 2

Now substitutes the values of b, c and d in the form of the equation below

∵ y = cot[b(t + c)] + d

∴ y=cot[2(t-\frac{1}{3})]+2

The equation of the cotangent function is y=cot[2(t-\frac{1}{3})]+2

Learn more:

You can learn more about trigonometry function in brainly.com/question/3568205

#LearnwithBrainly

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Answer:

(A) -0.2

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Step-by-step explanation:

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