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skad [1K]
4 years ago
7

Is this the correct answer?

Mathematics
2 answers:
Romashka [77]4 years ago
6 0
The answer is 25 5/8..
satela [25.4K]4 years ago
4 0

The answer is 25 5/8ths.

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Complete the table below y=mx+b
iVinArrow [24]

Answer:

I don't see a table or anything that has an attachment ????

Step-by-step explanation:

8 0
3 years ago
Which system of linear inequalities is graphed?
ANEK [815]

To determine the system of inequality that has been graphed, we need to be very smart.


Observe that all the equations are the same.


Also note that all the lines are solid. This should tell you that the inequities should involve.


\ge \:or\: \le



Therefore the answer is between option A and B.



So we choose a point in the solution region to discriminate between A and B.


Let us choose the origin since that is easy to evaluate.


We substitute into option A to get.

y\le 3x-1\:and\: x+ 3y \ge 6




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We now substitute into option B



y\ge 3x-1\:and\: x+ 3y \le 6




0\ge 3(0)-1\:and\: 0+ 3(0) \le 6




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8 0
3 years ago
Why would a box and whisker plot be unequal?
bearhunter [10]
Becasue the data may be skewed right or left (not symmetrical)

that is obvious when the median lean to left or right while the maximum and minimum records are still as they are.
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4 0
3 years ago
Can you help my brother with this question 3 pls
cricket20 [7]
They are not equivalent fractions. You will have to turn 3/4 into an 8th, so multiply it by two, (6/8) and plot that on a graph. 
7 0
3 years ago
Rewrite the function by completing the square. h(x)= x^{2} +3 x -18 left parenthesis, x, right parenthesis, equals, x, squared,
ludmilkaskok [199]

Answer:

  h(x) = (x +1.5)^2 -20.25

Step-by-step explanation:

We assume you want to rearrange h(x)= x^2 +3x -18.

Recognize the coefficient of x is 3. Add and subtract the square of half that. (3/2)^2 = 9/4 = 2.25

  h(x) = (x^2 +3x +2.25) -18 -2.25

Now, write the expression in parentheses as a square, simplify the constant.

  h(x) = (x +1.5)^2 -20.25 . . . . . . . . vertex form

4 0
3 years ago
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