Answer:
y = 5
Step-by-step explanation:
That "+5" elevates the graph of this cosine function 5 units above the x axis, and thus the "midline" you wanted is y = 5.
There are two <em>true</em> statements:
- When the function is composed with r, the <em>composite</em> function is V(t) = (1/48) · π · t⁶.
- V(r(6)) shows that the volume is 972π cubic inches after 6 seconds.
<h3>How to use composition between two function</h3>
Let be <em>f</em> and <em>g</em> two functions, there is a composition of <em>f</em> with respect to <em>g</em> when the domain of <em>f</em> is equal to the range of <em>g</em>. In this question, the <em>domain</em> variable of the function V(r) is replaced by substitution.
If we know that V(r) = (4/3) · π · r³ and r(t) = (1/4) · t², then the composite function is:
V(t) = (4/3) · π · [(1/4) · t²]³
V(t) = (4/3) · π · (1/64) · t⁶
V(t) = (1/48) · π · t⁶
There are two <em>true</em> statements:
- When the function is composed with r, the <em>composite</em> function is V(t) = (1/48) · π · t⁶.
- V(r(6)) shows that the volume is 972π cubic inches after 6 seconds.
To learn on composition between functions: brainly.com/question/12007574
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Answer:
B
Step-by-step explanation:
angles on the circumference of a circle subtended on the same arc are congruent , then
x = 52°
a) Since the corresponding y-value is -0.6, hence the point (-0.8, -0.6) is a solution to the system of equations
b) since the corresponding x-value is not 1/3, hence the point (1/3, 2) is not a solution to the system of equation
In order to show if the given point corresponds to the given function, we will have to substitute the value of x into the function to see if we will have its corresponding y-value
For the point (-0.8, -0.6), substitute x = -0.8 into both functions as shown:
f(x) = 2x + 1
f(-0.8) = 2(-0.8) + 1
f(-0.8) = -1.6 + 1
f(-0.8) = -0.6
Simiarly;
y = -3(-0.8)- 3
y = 2.4 - 3
y = -0.6
Since the corresponding y-value is -0.6, hence the point (-0.8, -0.6) is a solution to the system of equations
For the point (1/3, 2), substitute x = 1/3 into both functions as shown:
x = (y+2)/2
x = (2+2)/2
x = 4/2
x = 2
Simiarly;
x + 2 = 3
x = 3-2
x = 1
Since the corresponding x-value is not 1/3, hence the point (1/3, 2) is not a solution to the system of equations
Learn more on systems of equation here: brainly.com/question/847634
