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marysya [2.9K]
2 years ago
10

Help.me PLEASRRREEEEERERR

Mathematics
1 answer:
Marina86 [1]2 years ago
7 0

Answer:

The answer to your question is B

Step-by-step explanation:

just trust me :)

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15/13

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What is the multiplier for the table below? (Write multiplier as x.x)​
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The average rate of change is m = 5.934

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What is the value of this expression?<br> 2.3·23.623
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there is a cooler with 6 orange sodas, 6 root beers and 6 pepsi's. Terri reaches into the cooler and grabs a pepsi but terri doe
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3 years ago
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Which of the following shows that EFGH is a parallelogram for y=7 and z=9?
Anna35 [415]

Option B: m \angle F=m \angle G=120^{\circ} and m \angle E=60^{\circ}, so \angle E is supplementary to both \angle F and \angle G, so EFGH is a parallelogram.

Option C: m \angle F=m \angle G=120^{\circ} so EFGH is a parallelogram.

Option D: m \angle E+m \angle G=180^{\circ} so EFGH is a parallelogram.

Explanation:

Option A: m \angle E=m \angle F=60^{\circ} and m \angle G=120^{\circ} so \angle G is supplementary to both \angle E and \angle F, so EFGH is a parallelogram

Let us substitute y=7 and z=9 in m \angle E=(7y+11)^{\circ}, m \angle F=(17y+1)^{\circ} and m \angle G=(14z-6)^{\circ} to determine the exact measures the angles of the parallelogram.

Substituting, we get, m \angle E=60^{\circ}, m \angle F=m \angle G=120^{\circ}

Thus, m \angle E\neq m \angle F because the measures of these angles are not equal.

Hence, Option A is not the correct answer.

Option B:  m \angle F=m \angle G=120^{\circ} and m \angle E=60^{\circ}, so \angle E is supplementary to both \angle F and \angle G, so EFGH is a parallelogram.

Let us substitute y=7 and z=9 in m \angle E=(7y+11)^{\circ}, m \angle F=(17y+1)^{\circ} and m \angle G=(14z-6)^{\circ} to determine the exact measures the angles of the parallelogram.

Thus, substituting, we have, m \angle E=60^{\circ}, m \angle F=m \angle G=120^{\circ}

Hence, Option B is the correct answer.

Option C: m \angle F=m \angle G=120^{\circ} so EFGH is a parallelogram.

To determine the angles, let us substitute z=9 in  m \angle F=(17y+1)^{\circ} and m \angle G=(14z-6)^{\circ}

Thus, m \angle F=m \angle G=120^{\circ}

Since, the opposite angles of a parallelogram are equal, EFGH is a parallelogram.

Hence, Option C is the correct answer.

Option D: m \angle E+m \angle G=180^{\circ} so EFGH is a parallelogram.

Let us substitute y=7 and z=9 in m \angle E=(7y+11)^{\circ}, m \angle F=(17y+1)^{\circ} and m \angle G=(14z-6)^{\circ} to determine the exact measures the angles of the parallelogram.

Substituting, we have, m \angle E=60^{\circ}, m \angle F=m \angle G=120^{\circ}

Adding the angles E and G, we have,

m \angle E+m \angle G=60^{\circ}+120^{\circ}=180^{\circ}

By the property of parallelogram, any two adjacent angles add upto 180.

Thus, the adjacent angles E and G add upto 180.

Hence, Option D is the correct answer.

3 0
3 years ago
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